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Persamaan tetapan kesetimbangan air () ...

Pertanyaan

Persamaan tetapan kesetimbangan air (begin mathsize 14px style H subscript 2 O end style) ...undefined 

  1. begin mathsize 14px style K subscript w equals open square brackets H to the power of plus sign close square brackets equals open square brackets O H to the power of minus sign close square brackets end style 

  2. begin mathsize 14px style K subscript w double bond open square brackets H subscript 2 O close square brackets open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets end style 

  3. begin mathsize 14px style K subscript w double bond open square brackets H subscript 2 O close square brackets open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets end style 

  4. begin mathsize 14px style K subscript w equals fraction numerator open square brackets H subscript 2 O close square brackets over denominator open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets end fraction end style 

  5. begin mathsize 14px style K subscript w equals fraction numerator open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets over denominator open square brackets H subscript 2 O close square brackets end fraction end style 

Pembahasan Soal:

Berdasarkan persamaan reaksi kesetimbangan air

begin mathsize 14px style H subscript 2 O open parentheses italic l close parentheses yields and is yielded by H to the power of plus sign left parenthesis italic a italic q right parenthesis plus O H to the power of minus sign left parenthesis italic a italic q right parenthesis end style,

maka rumus tetapan kesetimbangan air adalah Error converting from MathML to accessible text.. Konsentrasi begin mathsize 14px style H subscript 2 O end style tidak dimasukkan ke dalam tetapan kesetimbangan karena dalam fase liquid.


Jadi, persamaan tetapan kesetimbangan air adalah Error converting from MathML to accessible text..undefined 

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

A. Acfreelance

Terakhir diupdate 07 Juni 2021

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Pertanyaan yang serupa

Jika harga tetapan kesetimbangan ion air sebesar  maka konsentrasi ion  pada air adalah ...

Pembahasan Soal:

Berdasarkan persamaan reaksi kesetimbangan air

begin mathsize 14px style H subscript 2 O open parentheses italic l close parentheses yields and is yielded by H to the power of plus sign left parenthesis italic a italic q right parenthesis plus O H to the power of minus sign left parenthesis italic a italic q right parenthesis end style,

maka rumus tetapan kesetimbangan air adalah Error converting from MathML to accessible text.. Karena begin mathsize 14px style open square brackets H to the power of plus sign close square brackets equals open square brackets O H to the power of minus sign close square brackets end style, sehingga:


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript w end cell equals cell open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets end cell row cell K subscript w end cell equals cell open square brackets O H to the power of minus sign close square brackets squared end cell row cell 10 to the power of negative sign 14 end exponent end cell equals cell open square brackets O H to the power of minus sign close square brackets squared end cell row cell 10 to the power of negative sign 7 end exponent end cell equals cell open square brackets O H to the power of minus sign close square brackets end cell end table end style 


Jadi, jawaban yang benar adalah A.undefined 

Roboguru

Diketahui pada suhu  harga tetapan kesetimbangan air = . Larutan  mempunyai pH = 2 - log 5, maka jumlah ion  pada suhu tersebut adalah ...

Pembahasan Soal:

Umumnya harga tetapan kesetimbangan air adalah begin mathsize 14px style 10 to the power of negative sign 14 end exponent end style pada suhu begin mathsize 14px style 25 space degree C end style, harga tetapan tersebut akan berubah ketika terjadi perubahan suhu. Berikut adalah rumus dari tetapan kesetimbangan air:


begin mathsize 14px style K subscript w equals open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets end style 


Sehingga untuk mencari jumlah ion begin mathsize 14px style O H to the power of minus sign space H N O subscript 3 end style dapet menggunakan informasi dari jumlah ion begin mathsize 14px style H to the power of plus sign space H N O subscript 3 end style. Perhitungannya sebagai berikut:


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript w end cell equals cell open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets end cell row cell 4 cross times 10 to the power of negative sign 12 end exponent end cell equals cell 5 cross times 10 to the power of negative sign 2 end exponent space open square brackets O H to the power of minus sign close square brackets end cell row cell 0 comma 8 cross times 10 to the power of negative sign 10 end exponent end cell equals cell open square brackets O H to the power of minus sign close square brackets end cell row cell 8 cross times 10 to the power of negative sign 11 end exponent end cell equals cell open square brackets O H to the power of minus sign close square brackets end cell end table end style 


Jadi, jawaban yang benar adalah D.

Roboguru

Air mengalami ionisasi menurut reaksi: , Jika pada suhu 292 K, Kw air = 1,0x10-14, maka air mumi memiliki konsentrasi H+ sama dengan konsentrasi OH- yaitu ...

Pembahasan Soal:

Tetapan kesetimbangan air Kw dinyatakan dengan:
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript w end cell equals cell fraction numerator open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets over denominator open square brackets H subscript 2 O close square brackets end fraction end cell row cell K subscript w open square brackets H subscript 2 O close square brackets end cell equals cell open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets end cell row cell K subscript w end cell equals cell open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets end cell row cell 1 comma 0 cross times 10 to the power of negative sign 14 end exponent end cell equals cell x squared end cell row x equals cell open square brackets H to the power of plus sign close square brackets equals open square brackets O H to the power of minus sign close square brackets equals 1 comma 0 cross times 10 to the power of negative sign 7 end exponent end cell end table end style 
 

Jadi, dapat disimpulkan jawaban yang tepat adalah A.

Roboguru

Jika  pada  dianggap , berapa konsentrasi ion  dan  dalam air murni pada suhu tersebut?

Pembahasan Soal:

Air murni merupakan larutan elektrolit lemah. Dengan menggunakan alat konduktometer yang sangat peka, hantaran arus listrik yang sangat lemah dapat dideteksi. Air murni mengalami ionisasi mengalami ionisasi menghasilkan ion H to the power of plus sign dan O H to the power of minus sign dalam jumlah yang sangat kecil. 

H subscript 2 O open parentheses italic l close parentheses equilibrium H to the power of plus sign left parenthesis italic a italic q right parenthesis plus O H to the power of minus sign left parenthesis italic a italic q right parenthesis 

K subscript w equals open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets 

Harga K subscript w dipengaruhi oleh suhu. Pada suhu tinggi air yang terionisasi semakin banyak, akibatnya jumlah ion H to the power of plus sign dan O H to the power of minus sign  semakin besar dan nilai K subscript w semakin besar. Sebagai perbandingan K subscript w pada 25 degree C equals 10 to the power of negative sign 14 end exponent sedangkan K subscript w pada 100 degree C equals 10 to the power of negative sign 12 end exponent dan dapat dihitung jumlah ion H to the power of plus sign dan O H to the power of minus sign yaitu sebagai berikut:

table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript w end cell equals cell open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets end cell row cell 10 to the power of negative sign 12 end exponent end cell equals cell open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets space dimana space open square brackets H to the power of plus sign close square brackets equals open square brackets O H to the power of minus sign close square brackets comma space maka end cell row cell 10 to the power of negative sign 12 end exponent end cell equals cell open square brackets 10 to the power of negative sign 6 end exponent close square brackets open square brackets 10 to the power of negative sign 6 end exponent close square brackets end cell end table 

Jadi konsentrasi H to the power of bold plus sign adalah bold 10 to the power of bold minus sign bold 6 end exponent M dan O H to the power of bold minus sign adalah bold 10 to the power of bold minus sign bold 6 end exponent M.space 

Roboguru

Tentukanlah  dalam larutan yang nilai pH-nya :

Pembahasan Soal:

Penentuan begin mathsize 14px style open square brackets H to the power of plus sign close square brackets space dan space open square brackets O H to the power of minus sign close square brackets end style berdasarkan hubungannya terhadap pH dan begin mathsize 14px style K subscript italic w end style (pH = begin mathsize 14px style 2 plus log space 5 end stylebegin mathsize 14px style K subscript italic w equals 1 cross times 10 to the power of negative sign 14 end exponent end style).

  • Penentuan begin mathsize 14px style open square brackets H to the power of plus sign close square brackets end style.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell 2 plus log space 5 end cell row pH equals cell 2 plus 0 comma 7 end cell row pH equals cell 2 comma 7 end cell row blank blank blank row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 10 to the power of negative sign pH end exponent end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 10 to the power of negative sign 2 comma 7 end exponent end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 2 cross times 10 to the power of negative sign 3 end exponent end cell end table end style  

  • Penentuan begin mathsize 14px style open square brackets O H to the power of minus sign close square brackets end style.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript italic w end cell equals cell open square brackets O H to the power of minus sign close square brackets cross times open square brackets H to the power of plus sign close square brackets end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell fraction numerator K subscript italic w over denominator open square brackets H to the power of plus sign close square brackets end fraction end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell fraction numerator 1 cross times 10 to the power of negative sign 14 end exponent over denominator 2 cross times 10 to the power of negative sign 3 end exponent end fraction end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 5 cross times 10 to the power of negative sign 12 end exponent end cell end table end style 


Jadi, nilai begin mathsize 14px style open square brackets H to the power of plus sign close square brackets end style dan begin mathsize 14px style open square brackets O H to the power of minus sign close square brackets end style berturut-turut adalah undefined dan begin mathsize 14px style 5 cross times 10 to the power of negative sign 12 end exponent end style. 

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