Iklan

Pertanyaan

Perhatikan sistem katrol berikut ini. Diketahui massa benda 1 dan benda 2 masing-masing 4 kg dan 2 kg dan percepatan gravitasi 10 m / s 2 . Benda 2 berada pada lintasan licin, dan massa katrol diabaikan. Hitunglah percepatan !

Perhatikan sistem katrol berikut ini.

Diketahui massa benda 1 dan benda 2 masing-masing 4 kg dan 2 kg dan percepatan gravitasi  . Benda 2 berada pada lintasan licin, dan massa katrol diabaikan. Hitunglah percepatan !

  1. begin mathsize 14px style straight m divided by straight s squared end style 

  2. begin mathsize 14px style straight m divided by straight s squared end style  

  3. begin mathsize 14px style straight m divided by straight s squared end style  

  4. begin mathsize 14px style straight m divided by straight s squared end style  

  5. begin mathsize 14px style straight m divided by straight s squared end style  

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

00

:

07

:

55

:

51

Iklan

Y. Maghfirah

Master Teacher

Jawaban terverifikasi

Pembahasan

Tinjau benda 1 Tinjau benda 2 Karena massa katrol diabaikan nilai Subtitusi persamaan 1 ke persamaan 2

 

Tinjau benda 1

begin mathsize 14px style sum straight F subscript 1 equals straight m subscript 1 straight a straight w subscript 1 minus straight T subscript 1 equals straight m subscript 1 straight a straight m subscript 1 straight g minus straight T subscript 1 equals straight m subscript 1 straight a straight T subscript 1 equals straight m subscript 1 straight g minus straight m subscript 1 straight a horizontal ellipsis. left parenthesis 1 right parenthesis end style 

Tinjau benda 2

begin mathsize 14px style sum straight F subscript 2 equals straight m subscript 2 straight a minus straight w subscript 2 sinθ plus straight T subscript 2 equals straight m subscript 2 straight a end style 

Karena massa katrol diabaikan nilai begin mathsize 14px style straight T subscript 1 equals straight T subscript 2 end style  

begin mathsize 14px style negative straight w subscript 2 sinθ plus straight T subscript 1 equals straight m subscript 2 straight a horizontal ellipsis left parenthesis 2 right parenthesis end style 

Subtitusi persamaan 1 ke persamaan 2

begin mathsize 14px style negative straight w subscript 2 sinθ plus straight m subscript 1 straight g minus straight m subscript 1 straight a equals straight m subscript 2 straight a minus straight m subscript 2 gsinθ plus straight m subscript 1 straight g equals straight m subscript 2 straight a plus straight m subscript 1 straight a straight g left parenthesis negative straight m subscript 2 sinθ plus straight m subscript 1 right parenthesis equals straight a left parenthesis straight m subscript 1 plus straight m subscript 2 right parenthesis straight a equals fraction numerator straight g left parenthesis straight m subscript 1 minus straight m subscript 2 sinθ right parenthesis over denominator left parenthesis straight m subscript 1 plus straight m subscript 2 right parenthesis end fraction straight a equals fraction numerator 10 left parenthesis 4 minus 2 open parentheses 1 half close parentheses over denominator 4 plus 2 end fraction equals fraction numerator 10 open parentheses 3 close parentheses over denominator 6 end fraction equals 30 over 6 equals 5 straight straight m divided by straight s squared end style 

Buka akses jawaban yang telah terverifikasi

lock

Yah, akses pembahasan gratismu habis


atau

Dapatkan jawaban pertanyaanmu di AiRIS. Langsung dijawab oleh bestie pintar

Tanya Sekarang

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

4

Iklan

Tanya ke AiRIS

Yuk, cobain chat dan belajar bareng AiRIS, teman pintarmu!