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Perhatikan reaksi fusi berikut ! Diketahui : Ma...

Perhatikan reaksi fusi berikut !

blank subscript 1 straight H to the power of 1 plus subscript 1 straight H to the power of 1 space rightwards arrow space subscript 1 straight d squared plus subscript 1 to the power of 0 straight e space plus space straight E

Diketahui : Massa blank subscript 1 straight H to the power of 1= 1,0078 sma

                 Massa blank subscript 1 straight d squared= 2,01410 sma

                 Massa blank subscript 1 to the power of 0 straight e = 0,00055 sma

                1 sma = 931 MeV

Nilai E (energi yang dihasilkan) pada reaksi fusi adalah ....

  1. 0,44 MeV

  2. 0,88 MeV

  3. 0,98 MeV

  4. 1,02 MeV

  5. 1,47 MeV

Jawaban:

Reaksi fusi yang terjadi sebagai berikut.

blank subscript 1 straight H to the power of 1 plus subscript 1 straight H to the power of 1 space rightwards arrow space subscript 1 straight d squared plus subscript 1 to the power of 0 straight e space plus space straight E

Hitung terlebih dahulu defek massa, yaitu :

increment straight m space equals space begin inline style sum for blank of end style straight m subscript kiri space minus space end subscript begin inline style sum for blank of end style straight m subscript kanan  space begin inline style increment end style begin inline style straight m end style begin inline style space end style begin inline style equals end style begin inline style space end style begin inline style open parentheses 1 comma 0078 space plus space 1 comma 0078 close parentheses end style begin inline style space end style begin inline style minus end style begin inline style space end style begin inline style open parentheses 2 comma 01410 plus 0 comma 00055 close parentheses end style begin inline style space end style  increment begin inline style straight m end style begin inline style space end style begin inline style equals end style begin inline style space end style begin inline style 2 end style begin inline style comma end style begin inline style 0156 end style begin inline style space end style begin inline style minus end style begin inline style space end style begin inline style 2 end style begin inline style comma end style begin inline style 01465 end style  space begin inline style increment end style begin inline style straight m end style begin inline style space end style begin inline style equals end style begin inline style space end style begin inline style 0 end style begin inline style comma end style begin inline style 00095 end style begin inline style space end style begin inline style straight s end style begin inline style straight m end style begin inline style straight a end style

Defek massa tersebut kemudian akan diubah menjadi energi ikat inti yang akan digunakan untuk mengikat proton-proton di dalam inti atom.

straight E subscript ikat equals space increment straight m cross times 931 space MeV over sma  straight E subscript ikat equals space open parentheses 0 comma 00095 close parentheses cross times 931 MeV over sma  straight E subscript ikat equals 0 comma 88445 space Mev  straight E subscript ikat space almost equal to space 0 comma 88 space MeV

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