Iklan

Iklan

Pertanyaan

Perhatikan grafik fungsi berikut. Berdasarkan grafik tersebut, nilai f ( 2 ) + f − 1 ( 3 ) adalah ...

Perhatikan grafik fungsi berikut.

 

Berdasarkan grafik tersebut, nilai  adalah ...

  1. 8 atau 3.

  2. 0 atau 8. 

  3. 8 atau 5. 

  4. 3 atau 0. 

  5. 1 atau 8. 

Iklan

R. RGFREELANCETIGASATU

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah E.

jawaban yang benar adalah E.

Iklan

Pembahasan

Berdasarkan grafik, titik potong sumbu X yaitu dan melalui titik . Persamaan Kuadrat jika diketahui 2 titik potong di sumbu X yaitu Maka Substitusikan maka Nilai Menghitung fungsi invers dapat menggunakan rumus berikut Karena maka jawaban akan ada dua, sehingga Dapatlah nilai yaitu atau Jadi, Nilai adalah 1 atau 8. Oleh karena itu, jawaban yang benar adalah E.

Berdasarkan grafik, titik potong sumbu X yaitu begin mathsize 14px style left parenthesis negative 1 comma 0 right parenthesis end style dan begin mathsize 14px style left parenthesis 4 comma 0 right parenthesis end style melalui titik begin mathsize 14px style left parenthesis negative 2 comma negative 3 right parenthesis end style.

Persamaan Kuadrat jika diketahui 2 titik potong di sumbu X yaitu

begin mathsize 14px style y equals a left parenthesis x minus x subscript 1 right parenthesis left parenthesis x minus x subscript 2 right parenthesis end style 

Maka

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell negative 3 end cell equals cell a left parenthesis negative 2 minus left parenthesis negative 1 right parenthesis right parenthesis left parenthesis negative 2 minus 4 right parenthesis end cell row cell negative 3 end cell equals cell a left parenthesis negative 1 right parenthesis left parenthesis negative 6 right parenthesis end cell row cell negative 3 end cell equals cell a left parenthesis 6 right parenthesis end cell row cell negative 3 end cell equals cell 6 a end cell row a equals cell fraction numerator negative 3 over denominator 6 end fraction end cell row a equals cell negative 1 half end cell end table end style 

Substitusikan

begin mathsize 14px style y equals negative 1 half left parenthesis x minus left parenthesis negative 1 right parenthesis right parenthesis left parenthesis x minus 4 right parenthesis end style 

begin mathsize 14px style y equals negative 1 half left parenthesis x plus 1 right parenthesis left parenthesis x minus 4 right parenthesis y equals negative 1 half left parenthesis x squared minus 3 x minus 4 right parenthesis y equals negative 1 half x squared plus 3 over 2 x plus 2 end style 

begin mathsize 14px style y equals f left parenthesis x right parenthesis end style maka begin mathsize 14px style f left parenthesis x right parenthesis equals negative 1 half x squared plus 3 over 2 x plus 2 end style 

Nilai begin mathsize 14px style f left parenthesis 2 right parenthesis equals negative 1 half left parenthesis 2 right parenthesis squared plus fraction numerator 3 over denominator 2 end fraction left parenthesis 2 right parenthesis plus 2 equals negative 2 plus 3 plus 2 equals 3 end style 
 

Menghitung fungsi invers dapat menggunakan rumus berikut

 begin mathsize 14px style f to the power of negative 1 end exponent left parenthesis x right parenthesis equals fraction numerator negative b plus-or-minus square root of b squared minus 4 a open parentheses c minus x close parentheses end root over denominator 2 a end fraction end style 
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f to the power of negative 1 end exponent left parenthesis negative 3 right parenthesis end cell equals cell fraction numerator negative begin display style 3 over 2 end style plus-or-minus square root of open parentheses begin display style 3 over 2 end style close parentheses squared minus 4 open parentheses negative begin display style 1 half end style close parentheses open parentheses 2 minus left parenthesis negative 3 right parenthesis close parentheses end root over denominator 2 open parentheses negative begin display style 1 half end style close parentheses end fraction end cell row cell f to the power of negative 1 end exponent left parenthesis negative 3 right parenthesis end cell equals cell fraction numerator negative begin display style 3 over 2 end style plus-or-minus square root of begin display style 9 over 4 end style plus 10 end root over denominator negative 1 end fraction end cell row cell f to the power of negative 1 end exponent left parenthesis negative 3 right parenthesis end cell equals cell fraction numerator negative begin display style 3 over 2 end style plus-or-minus square root of begin display style 49 over 4 end style end root over denominator negative 1 end fraction end cell row cell f to the power of negative 1 end exponent left parenthesis negative 3 right parenthesis end cell equals cell fraction numerator negative begin display style 3 over 2 end style plus-or-minus begin display style 7 over 2 end style over denominator negative 1 end fraction end cell row blank blank blank end table end style  

Karena begin mathsize 14px style plus-or-minus end style maka jawaban akan ada dua, sehingga

  •  begin mathsize 14px style left parenthesis plus right parenthesis end style  

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f to the power of negative 1 end exponent left parenthesis negative 3 right parenthesis end cell equals cell fraction numerator negative begin display style 3 over 2 end style plus begin display style 7 over 2 end style over denominator negative 1 end fraction end cell row blank equals cell fraction numerator begin display style 4 over 2 end style over denominator negative 1 end fraction end cell row blank equals cell fraction numerator 2 over denominator negative 1 end fraction end cell row blank equals cell negative 2 end cell end table end style   

  •  begin mathsize 11px style left parenthesis negative right parenthesis end style

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f to the power of negative 1 end exponent left parenthesis negative 3 right parenthesis end cell equals cell fraction numerator negative begin display style 3 over 2 end style minus begin display style 7 over 2 end style over denominator negative 1 end fraction end cell row blank equals cell fraction numerator negative begin display style 10 over 2 end style over denominator negative 1 end fraction end cell row blank equals cell fraction numerator negative 5 over denominator negative 1 end fraction end cell row blank equals 5 end table end style 

Dapatlah nilai begin mathsize 14px style f to the power of negative 1 end exponent left parenthesis 3 right parenthesis end style yaitu begin mathsize 14px style negative 2 end style atau begin mathsize 14px style 5 end style 

Jadi,

  • begin mathsize 14px style f left parenthesis 2 right parenthesis plus f to the power of negative 1 end exponent left parenthesis 3 right parenthesis equals 3 plus left parenthesis negative 2 right parenthesis equals 1 end style 
  • begin mathsize 14px style f left parenthesis 2 right parenthesis plus f to the power of negative 1 end exponent left parenthesis 3 right parenthesis equals 3 plus 5 equals 8 end style

Nilai begin mathsize 14px style f left parenthesis 2 right parenthesis plus f to the power of negative 1 end exponent left parenthesis 3 right parenthesis end style adalah 1 atau 8.

Oleh karena itu, jawaban yang benar adalah E.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Iklan

Pertanyaan serupa

Jika f − 1 ( x ) = 3 x − 6 , nilai f ( 0 ) = ....

8

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia