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Perhatikan gambar di bawah! Jika sistem benda bergerak, jika koefisien gesekan antara balok dan lantai 0,5 dan percepatan gravitasi 10 m/s2, maka besarnya percepatan sistem adalah ...

Pertanyaan

Perhatikan gambar di bawah!

Jika sistem benda bergerak, jika koefisien gesekan antara balok dan lantai 0,5 dan percepatan gravitasi 10 m/s2, maka besarnya percepatan sistem adalah ...

  1. 2 m/s2

  2. 3 m/s2

  3. 4 m/s2

  4. 5 m/s2

  5. 6 m/s2

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell sum begin inline style F subscript x end style begin inline style equals end style begin inline style m end style begin inline style times end style begin inline style a end style end cell row blank blank cell begin inline style T end style begin inline style minus end style begin inline style f end style begin inline style equals end style begin inline style m end style begin inline style times end style begin inline style a end style end cell row blank blank cell begin inline style T end style begin inline style equals end style begin inline style f end style begin inline style plus end style begin inline style m end style begin inline style times end style begin inline style a end style end cell row blank blank cell begin inline style equals end style begin inline style mu end style begin inline style times end style begin inline style N end style begin inline style plus end style begin inline style m end style begin inline style times end style begin inline style a end style end cell row blank equals cell begin inline style 0 end style begin inline style comma end style begin inline style 5 end style begin inline style times end style begin inline style 20 end style begin inline style plus end style begin inline style 2 end style begin inline style times end style begin inline style a end style end cell row blank blank cell begin inline style equals end style begin inline style 10 end style begin inline style plus end style begin inline style 2 end style begin inline style a end style end cell end table

Diketahui:

mu equals 0 comma 5 g equals 10 space bevelled straight m over straight s squared

Ditanya: a

Jawab:

Analisis balok 2 kg

table attributes columnalign right center left columnspacing 0px end attributes row cell begin inline style sum for blank of end style F subscript y end cell equals 0 row cell W minus N end cell equals 0 row N equals W row N equals cell m cross times g end cell row blank equals cell 2 cross times 10 end cell row blank equals cell 20 space N end cell end table

table attributes columnalign right center left columnspacing 0px end attributes row cell begin inline style sum for blank of end style F subscript x end cell equals cell m times a end cell row cell T minus f end cell equals cell m times a end cell row T equals cell f plus m times a end cell row blank equals cell mu times N plus m times a end cell row blank equals cell 0 comma 5 times 20 plus 2 times a end cell row blank equals cell 10 plus 2 a end cell end table

Analisis balok 8 kg (Pada soal tidak diketahui sudut yang terbentuk antara gaya dengan garis normal, dalam perhitungan ini dimisalkan sudutnya adalah 30°)

table attributes columnalign right center left columnspacing 0px end attributes row cell sum for blank of F subscript y end cell equals 0 row cell W minus N minus F subscript y end cell equals 0 row N equals cell W minus F subscript y end cell row N equals cell m cross times g minus F space sin space 30 end cell row blank equals cell 8 cross times 10 minus 100 times 0 comma 5 end cell row blank equals cell 30 space N end cell end table

table attributes columnalign right center left columnspacing 0px end attributes row cell sum for blank of F blank subscript x end cell equals cell m times a end cell row cell F blank subscript x minus T minus f end cell equals cell m times a end cell row cell F space cos space 30 minus T minus mu times N end cell equals cell m times a end cell row cell 100 space cos space 30 minus T minus 0 comma 5 times 30 end cell equals cell 8 times a end cell end table
table attributes columnalign right center left columnspacing 0px end attributes row cell 100 times 0 comma 87 minus open parentheses 10 plus 2 a close parentheses minus 15 end cell equals cell 8 a end cell row cell 87 minus 10 minus 2 a minus 15 end cell equals cell 8 a end cell row 62 equals cell 10 space a end cell row a equals cell 6 comma 2 space bevelled straight m over straight s squared end cell end table

Karena tidak ada pilihan jawaban yang tepat, maka jawaban dibulatkan ke bawah menjadi 6 m/s2.

        
Jadi, jawaban yang tepat adalah E.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 19 Mei 2021

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