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Pertanyaan

Perhatikan gambar berikut!

  

Diketahui massa kedua bola sama. Selanjutnya, perhatikan pernyataan berikut!

  1. Jika tumbukan tidak lenting, jumlah momentum sebelum dan sesudah tumbukan sama.
  2. Jika tumbukan tidak lenting, begin mathsize 14px style v to the power of apostrophe subscript A equals v to the power of apostrophe subscript B equals 3 space straight m divided by straight s end style.
  3. Jika tumbukan lenting sempurna, bola B tetap diam dan bola A bergerak begin mathsize 14px style negative 7 space straight m divided by straight s end style (berlawanan).
  4. Jika tumbukan lenting sempurna, bola A diam dan bola B bergerak dengan kecepatan begin mathsize 14px style 7 space straight m divided by straight s end style.

Pernyataan yang benar ditunjukkan pada angka...undefined 

  1. 1 dan 3undefined 

  2. 1 dan 4undefined 

  3. 2 dan 3undefined 

  4. 2 dan 4undefined 

  5. 3 dan 4undefined 

S. Syifa

Master Teacher

Jawaban terverifikasi

Pembahasan

Diketahui: 

begin mathsize 12px style m subscript A equals m subscript B end style

begin mathsize 12px style v subscript A equals 7 space m divided by s end style

begin mathsize 12px style v subscript B equals 0 end style

Pembahasan:

1. Jika tumbukan tidak lenting jumlah momentum sebelum dan sesudah tumbukan sama

begin mathsize 12px style p equals p apostrophe end style

begin mathsize 12px style m subscript A. v subscript A equals left parenthesis m subscript A plus m subscript B right parenthesis. v apostrophe end style

dengan begin mathsize 12px style v subscript A apostrophe equals v subscript B apostrophe equals v apostrophe end style (tumbukan tidak lenting)

PERNYATAAN (1) BENAR

2. Jika tumbukan tidak lenting, size 12px v subscript size 12px A size 12px apostrophe size 12px equals size 12px v subscript size 12px B size 12px apostrophe size 12px equals size 12px 3 size 12px space size 12px m size 12px divided by size 12px s

begin mathsize 12px style p equals p apostrophe end style

begin mathsize 12px style m subscript A. v subscript A equals left parenthesis m subscript A plus m subscript B right parenthesis. v apostrophe end style

begin mathsize 12px style m subscript A. left parenthesis 7 space m divided by s right parenthesis equals left parenthesis m subscript A plus m subscript A right parenthesis. v apostrophe end style

size 12px m subscript size 12px A size 12px. size 12px left parenthesis size 12px 7 size 12px space size 12px m size 12px divided by size 12px s size 12px right parenthesis size 12px equals size 12px 2 size 12px. size 12px m subscript size 12px A size 12px. size 12px v size 12px apostrophe

begin mathsize 12px style v apostrophe equals fraction numerator 7 space m divided by s over denominator 2 end fraction end style

begin mathsize 12px style v apostrophe equals 3 comma 5 space m divided by s end style

PERNYATAAN (2) SALAH

3. Jika tumbukan lenting sempurna bola B tetap diam dan bola A bergerak begin mathsize 12px style negative 7 space m divided by s end style (berlawanan)

4. Jika tumbukan lenting sempurna bola A diam dan bola B bergerak dengan kecepatan begin mathsize 12px style 7 space m divided by s end style

Tumbukan lenting sempurna maka, begin mathsize 12px style e equals 1 end style

begin mathsize 12px style negative fraction numerator v subscript B apostrophe minus v subscript A apostrophe over denominator v subscript B minus v subscript A end fraction equals 1 end style

size 12px minus fraction numerator size 12px v subscript size 12px B size 12px apostrophe size 12px minus size 12px v subscript size 12px A size 12px apostrophe over denominator size 12px 0 size 12px minus size 12px v subscript size 12px A end fraction size 12px equals size 12px 1

begin mathsize 12px style v subscript A apostrophe minus v subscript B apostrophe equals negative v subscript A end style

begin mathsize 12px style v subscript A apostrophe equals v subscript B apostrophe minus 7 space m divided by s end style ... (1)

Kecepatan akhir B (substitusikan pers.1 ke hukum kekekalan momentum)

undefined

begin mathsize 12px style m subscript A. v subscript A equals m subscript A. v subscript A apostrophe plus m subscript B. v subscript B apostrophe end style

size 12px v subscript size 12px A size 12px equals size 12px left parenthesis size 12px v subscript size 12px B size 12px apostrophe size 12px minus size 12px 7 size 12px space size 12px m size 12px divided by size 12px s size 12px right parenthesis size 12px plus size 12px v subscript size 12px B size 12px apostrophe

begin mathsize 12px style 7 space m divided by s space equals space 2 space v subscript B apostrophe minus 7 space m divided by s end style

begin mathsize 12px style 14 space m divided by s space equals space 2 space v subscript B apostrophe end style

begin mathsize 12px style v subscript B apostrophe equals 7 space m divided by s end style

Kecepatan akhir A

begin mathsize 12px style v subscript A apostrophe equals v subscript B apostrophe minus 7 space m divided by s end style

size 12px v subscript size 12px A size 12px apostrophe size 12px equals size 12px 7 size 12px space size 12px m size 12px divided by size 12px s size 12px space size 12px minus size 12px 7 size 12px space size 12px m size 12px divided by size 12px s

begin mathsize 12px style v subscript A apostrophe equals 0 space end style (diam)

PERNYATAAN (3) SALAH

PERNYATAAN (4) BENAR

Jadi, jawaban yang tepat adalah B (1 dan 4)

 

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