Iklan

Pertanyaan

Perhatikan data potensial reduksi standar berikut! Fe 2 + + 2 e − → Fe E 0 = − 0 , 44 V Pb 2 + + 2 e − → Pb E 0 = − 0 , 13 V Zn 2 + + 2 e − → Zn E 0 = − 0 , 76 V Sn 2 + + 2 e − → Sn E 0 = − 0 , 14 V Reaksi yang dapat berlangsung dalam keadaan spontan dan memiliki E 0 sel terbesar adalah ....

Perhatikan data potensial reduksi standar berikut!

  

Reaksi yang dapat berlangsung dalam keadaan spontan dan memiliki  sel terbesar adalah ....

  1. begin mathsize 14px style Fe to the power of 2 plus sign and Zn yields Fe and Zn to the power of 2 plus sign end style 

  2. begin mathsize 14px style Pb to the power of 2 plus sign and Fe yields Pb and Fe to the power of 2 plus sign end style 

  3. begin mathsize 14px style Zn and Pb to the power of 2 plus sign yields Zn to the power of 2 plus sign and Pb end style 

  4. begin mathsize 14px style Sn to the power of 2 plus sign and Zn yields Sn and Zn to the power of 2 plus sign end style 

  5. begin mathsize 14px style Zn to the power of 2 plus sign and Pb yields Zn and Pb to the power of 2 plus sign end style 

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

02

:

13

:

35

:

10

Klaim

Iklan

M. Robo

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah C.

jawaban yang tepat adalah C.

Pembahasan

Opsi A: Opsi B: Opsi C: Opsi D: Opsi E: Dengan demikian, reaksi yang dapat berlangsung dalam keadaan spontan dan memiliki sel terbesar adalah . Jadi, jawaban yang tepat adalah C.

Opsi A:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell E to the power of 0 subscript sel end cell equals cell E to the power of 0 subscript reduksi – E to the power of 0 subscript oksidasi end cell row cell E to the power of 0 subscript sel end cell equals cell left parenthesis minus sign 0 comma 44 space V right parenthesis minus sign left parenthesis minus sign 0 comma 76 space V right parenthesis end cell row cell E to the power of 0 subscript sel end cell equals cell negative sign 0 comma 44 space V plus 0 comma 76 space V end cell row cell E to the power of 0 subscript sel end cell equals cell plus 0 comma 32 space V space left parenthesis berlangsung space spontan right parenthesis end cell end table end style 
 

Opsi B:

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell E to the power of 0 subscript sel end cell equals cell E to the power of 0 subscript reduksi – E to the power of 0 subscript oksidasi end cell row cell E to the power of 0 subscript sel end cell equals cell left parenthesis minus sign 0 comma 13 space V right parenthesis minus sign left parenthesis minus sign 0 comma 44 space V right parenthesis end cell row cell E to the power of 0 subscript sel end cell equals cell negative sign 0 comma 13 space V plus 0 comma 44 space V end cell row cell E to the power of 0 subscript sel end cell equals cell plus 0 comma 31 space V space left parenthesis berlangsung space spontan right parenthesis end cell end table end style  


Opsi C:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell E to the power of 0 subscript sel end cell equals cell E to the power of 0 subscript reduksi – E to the power of 0 subscript oksidasi end cell row cell E to the power of 0 subscript sel end cell equals cell left parenthesis minus sign 0 comma 13 space V right parenthesis minus sign left parenthesis minus sign 0 comma 76 space V right parenthesis end cell row cell E to the power of 0 subscript sel end cell equals cell negative sign 0 comma 13 space V plus 0 comma 76 space V end cell row cell E to the power of 0 subscript sel end cell equals cell plus 0 comma 63 space V space left parenthesis berlangsung space spontan right parenthesis end cell end table end style 


Opsi D:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell E to the power of 0 subscript sel end cell equals cell E to the power of 0 subscript reduksi – E to the power of 0 subscript oksidasi end cell row cell E to the power of 0 subscript sel end cell equals cell left parenthesis minus sign 0 comma 14 space V right parenthesis minus sign left parenthesis minus sign 0 comma 76 space V right parenthesis end cell row cell E to the power of 0 subscript sel end cell equals cell negative sign 0 comma 14 space V plus 0 comma 76 space V end cell row cell E to the power of 0 subscript sel end cell equals cell plus 0 comma 62 space V space left parenthesis berlangsung space spontan right parenthesis end cell end table end style 


Opsi E:

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell E to the power of 0 subscript sel end cell equals cell E to the power of 0 subscript reduksi – E to the power of 0 subscript oksidasi end cell row cell E to the power of 0 subscript sel end cell equals cell left parenthesis minus sign 0 comma 76 space V right parenthesis minus sign left parenthesis minus sign 0 comma 13 space V right parenthesis end cell row cell E to the power of 0 subscript sel end cell equals cell negative sign 0 comma 76 space V plus 0 comma 13 space V end cell row cell E to the power of 0 subscript sel end cell equals cell negative sign 0 comma 63 space V space left parenthesis berlangsung space tidak space spontan right parenthesis end cell end table end style 


Dengan demikian, reaksi yang dapat berlangsung dalam keadaan spontan dan memiliki begin mathsize 14px style E to the power of 0 end style sel terbesar adalah

begin mathsize 14px style Zn and Pb to the power of 2 plus sign yields Zn to the power of 2 plus sign and Pb end style.

Jadi, jawaban yang tepat adalah C.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

7

alinn

Pembahasan lengkap banget

Iklan

Pertanyaan serupa

Perhatikan data potensial reduksi standar berikut! Cd 2 + ( aq ) + 2 e − → Cd ( s ) E 0 = − 0 , 40 V Cu 2 + ( aq ) + 2 e − → Cu ( s ) E 0 = + 0 , 34 V Harga E 0 sel ​ dari persamaan reaksi spont...

2

4.4

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia