Partikel bermuatan +65, +48, dan - 95 μC diletakkan pada garis. Yang berada ditengah pada jarak 0,35 m dari dua yang lainnya. Hitung gaya neto pada setiap muatan yang disebabkan oleh dua yang lainnya.

Pertanyaan

Partikel bermuatan +65, +48, dan - 95 mu straight C diletakkan pada garis. Yang berada ditengah pada jarak 0,35 m dari dua yang lainnya. Hitung gaya neto pada setiap muatan yang disebabkan oleh dua yang lainnya. 

R. Mutia

Master Teacher

Mahasiswa/Alumni Universitas Gadjah Mada

Jawaban terverifikasi

Jawaban

besar F1 , Fdan F3 berturut-turut adalah115,83 N , 788,69 N dan 443,38 N.

Pembahasan

Soal ini menanyakan tentang gaya coulomb yang terjadi pada muatan yang dipengaruhi oleh dua muatan lain.

Diketahui:

q subscript 1 equals plus 65 mu straight C equals plus 65 cross times 10 to the power of negative 6 end exponent straight C q subscript 2 equals plus 48 μC equals plus 48 cross times 10 to the power of negative 6 end exponent straight C q subscript 3 equals negative 95 μC equals negative 95 cross times 10 to the power of negative 6 end exponent straight C r subscript 12 equals r subscript 23 equals 0 comma 35 straight m

Ditanya: F1 , Fdan F3

Penyelesaian:

F subscript 1 equals F subscript 12 minus F subscript 13 F subscript 1 equals k fraction numerator q subscript 1 italic. q subscript 2 over denominator r subscript 12 to the power of italic 2 end fraction minus k fraction numerator q subscript italic 1 italic. q subscript 3 over denominator r subscript 13 to the power of italic 2 end fraction F subscript 1 equals 9 cross times 10 to the power of 9 open parentheses fraction numerator 65 cross times 10 to the power of negative 6 end exponent. space 48 cross times 10 to the power of negative 6 end exponent over denominator 0 comma 35 squared end fraction minus fraction numerator 65 cross times 10 to the power of negative 6 end exponent. space 95 cross times 10 to the power of negative 6 end exponent over denominator 0 comma 70 squared end fraction close parentheses F subscript 1 equals 9 cross times 10 to the power of 9 open parentheses 25 comma 47 cross times 10 to the power of negative 9 end exponent minus 12 comma 60 cross times 10 to the power of negative 9 end exponent close parentheses F subscript 1 equals 115 comma 83 space straight N  F subscript 2 equals F subscript 23 minus F subscript 21 F subscript 2 equals k fraction numerator q subscript 2 italic. q subscript 3 over denominator r subscript 23 to the power of italic 2 end fraction plus k fraction numerator q subscript italic 1 italic. q subscript italic 2 over denominator r subscript 12 to the power of italic 2 end fraction F subscript 2 equals 9 cross times 10 to the power of 9 open parentheses fraction numerator 48 cross times 10 to the power of negative 6 end exponent. space 95 cross times 10 to the power of negative 6 end exponent over denominator 0 comma 35 squared end fraction plus fraction numerator 65 cross times 10 to the power of negative 6 end exponent. space 95 cross times 10 to the power of negative 6 end exponent over denominator 0 comma 35 squared end fraction close parentheses F subscript 2 equals 788 comma 69 space straight N  F subscript 3 equals F subscript 32 minus F subscript 31 F subscript 3 equals k fraction numerator q subscript 3 italic. q subscript 2 over denominator r subscript 12 to the power of italic 2 end fraction plus k fraction numerator q subscript italic 1 italic. q subscript 3 over denominator r subscript 13 to the power of italic 2 end fraction F subscript 3 equals 9 cross times 10 to the power of 9 open parentheses fraction numerator 95 cross times 10 to the power of negative 6 end exponent. space 48 cross times 10 to the power of negative 6 end exponent over denominator 0 comma 35 squared end fraction plus fraction numerator 65 cross times 10 to the power of negative 6 end exponent. space 95 cross times 10 to the power of negative 6 end exponent over denominator 0 comma 70 squared end fraction close parentheses F subscript 3 equals 9 cross times 10 to the power of 9 open parentheses 37 comma 22 cross times 10 to the power of negative 9 end exponent plus 12 comma 60 cross times 10 to the power of negative 9 end exponent close parentheses F subscript 3 equals 443 comma 38 space straight N

Jadi besar F1 , Fdan F3 berturut-turut adalah115,83 N , 788,69 N dan 443,38 N.

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