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Pada suhu tertutup yang tekanannya 10 atm, terdapa...

Pada suhu tertutup yang tekanannya 10 atm, terdapat dalam keadaan setimbang 0,3 mol gas begin mathsize 14px style S O subscript 3 end style; 0,1 mol gas begin mathsize 14px style S O subscript 2 end style; 0,1 mol begin mathsize 14px style O subscript 2 end style dengan reaksi:

begin mathsize 14px style 2 S O subscript 3 open parentheses italic g close parentheses equilibrium 2 S O subscript 2 open parentheses italic g close parentheses and O subscript 2 open parentheses italic g close parentheses end style 

Nilai undefined pada suhu tersebut adalah ....undefined 

  1. 36 atmundefined 

  2. 18 atmundefined 

  3. 19 atmundefined 

  4. 4,5 atm undefined 

  5. 0,05 atm undefined 

Jawaban:

Reaksi kesetimbangan:

begin mathsize 14px style 2 S O subscript 3 open parentheses italic g close parentheses equilibrium 2 S O subscript 2 open parentheses italic g close parentheses and O subscript 2 open parentheses italic g close parentheses end style 

Tahap 1, cari tekanan parsial masing-masing gas:
Gunakan mol saat setimbang

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n space total space end cell equals cell space n space S O subscript 3 space plus space n space S O subscript 2 space plus space n space O subscript 2 end cell row blank equals cell space 0 comma 3 space plus space 0 comma 1 space plus space 0 comma 1 end cell row blank equals cell space 0 comma 5 space mol end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell P space S O subscript 3 space end cell equals cell space fraction numerator n space S O subscript 3 over denominator n space total end fraction cross times P space total end cell row blank equals cell fraction numerator 0 comma 3 over denominator 0 comma 5 end fraction cross times 10 end cell row blank equals cell space 6 space atm end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell P space S O subscript 2 space end cell equals cell space fraction numerator n space S O subscript 2 over denominator n space total end fraction cross times P space total end cell row blank equals cell fraction numerator 0 comma 1 over denominator 0 comma 5 end fraction cross times 10 end cell row blank equals cell space 2 space atm end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell P space O subscript 2 space end cell equals cell space fraction numerator n space O subscript 2 over denominator n space total end fraction cross times P space total end cell row blank equals cell fraction numerator 0 comma 1 over denominator 0 comma 5 end fraction cross times 10 end cell row blank equals cell space 2 space atm end cell end table end style 

Tahap 2, cari nilai begin mathsize 14px style K subscript p end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript p space end cell equals cell space fraction numerator left parenthesis P space S O subscript 2 right parenthesis squared space left parenthesis P space O subscript 2 right parenthesis over denominator left parenthesis P space S O subscript 3 right parenthesis squared end fraction end cell row blank equals cell space fraction numerator left parenthesis 2 right parenthesis squared space left parenthesis 2 right parenthesis over denominator left parenthesis 6 right parenthesis squared end fraction end cell row blank equals cell space 0 comma 2 end cell end table end style 

Jadi, tidak ada jawaban yang benar.

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