Pertanyaan

Nilai sin 4 5 ∘ − cos 27 0 ∘ − tan 15 0 ∘ sin 31 5 ∘ + cos 13 5 ∘ + tan 21 0 ∘ = ...

Nilai $\frac{sin 31 5 ^{\circ} + cos 13 5 ^{\circ} + tan 21 0 ^{\circ}}{sin 4 5 ^{\circ} - cos 27 0 ^{\circ} - tan 15 0 ^{\circ}} = ...$

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Habis dalam

Klaim

L. Rante

Master Teacher

Mahasiswa/Alumni Universitas Negeri Makassar

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

Pembahasan

Berdasarkan tabel trignonometri sudut istimewa, diperoleh Dengan demikian, jawaban yang tepat adalah B.

Berdasarkan tabel trignonometri sudut istimewa, diperoleh

$table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator sin space 315 degree plus cos space 135 degree plus tan space 210 degree over denominator sin space 45 degree minus cos space 270 degree minus tan space 150 degree end fraction end cell equals cell fraction numerator open parentheses negative begin display style 1 half end style square root of 2 close parentheses plus open parentheses negative begin display style 1 half end style square root of 2 close parentheses plus begin display style 1 third end style square root of 3 over denominator begin display style 1 half end style square root of 2 minus 0 minus open parentheses negative begin display style 1 third end style square root of 3 close parentheses end fraction end cell row blank equals cell fraction numerator negative square root of 2 plus begin display style 1 third end style square root of 3 over denominator begin display style 1 half end style square root of 2 plus begin display style 1 third end style square root of 3 end fraction end cell row blank equals cell fraction numerator negative square root of 2 plus begin display style 1 third end style square root of 3 over denominator begin display style 1 half square root of 2 plus 1 third square root of 3 end style end fraction cross times fraction numerator 1 half square root of 2 minus 1 third square root of 3 over denominator 1 half square root of 2 minus 1 third square root of 3 end fraction end cell row blank equals cell fraction numerator negative 1 plus begin display style 1 third end style square root of 6 plus begin display style 1 over 6 end style square root of 6 minus begin display style 1 third end style over denominator begin display style 1 half end style minus begin display style 1 third end style end fraction end cell row blank equals cell fraction numerator negative begin display style 4 over 3 end style plus begin display style 3 over 6 end style square root of 6 over denominator begin display style 1 over 6 end style end fraction end cell row blank equals cell fraction numerator begin display style fraction numerator negative 8 plus 3 square root of 6 over denominator 6 end fraction end style over denominator begin display style 1 over 6 end style end fraction end cell row blank equals cell 3 square root of 6 minus 8 end cell end table$

Dengan demikian, jawaban yang tepat adalah B.