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Pertanyaan

Nilai x → p lim ​ sin x − sin p ( x p ​ − 1 ) ​ = ...

Nilai

  1. fraction numerator 1 over denominator p sin space p end fraction

  2. fraction numerator 1 over denominator p space cos italic space p end fraction

  3. negative fraction numerator 1 over denominator p space cos space p end fraction

  4. negative fraction numerator 1 over denominator p space sin space x end fraction

  5. negative fraction numerator 1 over denominator x space sin space p end fraction

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N. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Padang

Jawaban terverifikasi

Pembahasan

table attributes columnalign right center left columnspacing 0px end attributes row cell limit as straight x rightwards arrow straight p of fraction numerator open parentheses begin display style p over x minus 1 end style close parentheses over denominator sin space x minus sin space p end fraction end cell equals cell limit as straight x rightwards arrow straight p of minus open parentheses fraction numerator straight x minus straight p over denominator x end fraction close parentheses times fraction numerator 1 over denominator sin space x minus sin space p end fraction end cell row blank equals cell limit as straight x rightwards arrow straight p of minus fraction numerator down diagonal strike x minus p end strike over denominator x times 2 space cos space 1 half open parentheses x plus p close parentheses times down diagonal strike sin space begin display style 1 half end style down diagonal strike open parentheses x minus p close parentheses end strike end fraction end cell row blank equals cell limit as straight x rightwards arrow straight p of minus fraction numerator 1 over denominator x. cos 1 half open parentheses x plus p close parentheses end fraction end cell row blank equals cell negative fraction numerator 1 over denominator p space cos space p end fraction end cell end table

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Hitung dan tentukan limit berikut ini! x → ∞ lim ​ x 3 sin x 1 ​ ( sec x 1 ​ − 1 ) = ...

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