Pertanyaan

Nilai x yang memenuhi persamaan adalah....

Nilai x yang memenuhi persamaan

$fraction numerator 3 open parentheses 4 x minus 6 close parentheses over denominator 2 end fraction minus 3 over 4 equals fraction numerator x plus 6 over denominator 3 end fraction$

adalah....

A. Acfreelance

Master Teacher

Jawaban terverifikasi

Pembahasan

Nilai x yang memenuhi adalah :

$fraction numerator 3 open parentheses 4 x minus 6 close parentheses over denominator 2 end fraction minus 3 over 4 equals fraction numerator x plus 6 over denominator 3 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space left parenthesis k e d u a space r u a s space d i k a l i space 12 right parenthesis 18 open parentheses 4 x minus 6 close parentheses minus 9 equals 4 open parentheses x plus 6 close parentheses 72 x minus 108 minus 9 equals 4 x plus 24 72 x minus 4 x equals 24 plus 108 plus 9 68 x equals 141 x equals 141 over 68$