Pertanyaan

Nilai dari

Nilai dari $limit as x rightwards arrow infinity of invisible function application fraction numerator open parentheses x squared minus 4 close parentheses tan invisible function application open parentheses x plus 2 close parentheses over denominator sin squared invisible function application open parentheses x plus 2 close parentheses end fraction equals....$

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Habis dalam

Klaim

D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

$limit as x rightwards arrow p of invisible function application fraction numerator sin invisible function application a x over denominator b x end fraction equals a over b limit as x rightwards arrow p of invisible function application fraction numerator tan invisible function application a x over denominator b x end fraction equals a over b M a k a box enclose limit as x rightwards arrow infinity of invisible function application fraction numerator open parentheses x squared minus 4 close parentheses tan invisible function application open parentheses x plus 2 close parentheses over denominator sin squared invisible function application open parentheses x plus 2 close parentheses end fraction equals limit as x rightwards arrow infinity of invisible function application fraction numerator open parentheses x plus 2 close parentheses open parentheses x minus 2 close parentheses tan invisible function application open parentheses x plus 2 close parentheses over denominator sin invisible function application open parentheses x plus 2 close parentheses sin invisible function application open parentheses x plus 2 close parentheses end fraction equals limit as x rightwards arrow infinity of invisible function application open parentheses x plus 2 close parentheses times limit as x rightwards arrow infinity of invisible function application fraction numerator open parentheses x minus 2 close parentheses over denominator sin invisible function application open parentheses x plus 2 close parentheses end fraction times limit as x rightwards arrow infinity of invisible function application fraction numerator tan invisible function application open parentheses x plus 2 close parentheses over denominator sin invisible function application open parentheses x plus 2 close parentheses end fraction end enclose$