Iklan

Pertanyaan

Nilai dari adalah....

Nilai dari integral subscript square root of 6 end subscript superscript 3 square root of 2 end superscript x square root of x squared minus 2 end root d x adalah....

  1. 24

  2. 18 2 over 3

  3. 18

  4. 17 1 third

  5. 17

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

01

:

03

:

11

:

56

Klaim

Iklan

A. Acfreelance

Master Teacher

Jawaban terverifikasi

Pembahasan

Misalkan maka ,kemudian dengan menggunakan integral substitusi akan didapat: Substitusikan kembali nilai t ke awal, sehinggi diperoleh: maka

Misalkan t equals x squared minus 2 maka fraction numerator d t over denominator d x end fraction equals 2 x rightwards arrow d x equals fraction numerator 1 over denominator 2 x end fraction d t, kemudian dengan menggunakan integral substitusi akan didapat:

integral x square root of x squared minus 2 end root d x equals integral x square root of t fraction numerator 1 over denominator 2 x end fraction d t equals integral fraction numerator square root of t over denominator 2 end fraction d t equals 1 half integral square root of t d t equals 1 half cross times fraction numerator 2 t square root of t over denominator 3 end fraction equals 1 third t square root of t

Substitusikan kembali nilai t ke awal, sehinggi diperoleh:

integral x square root of x squared minus 2 end root d x equals 1 third open parentheses x squared minus 2 close parentheses square root of x squared minus 2 end root plus c

maka

table attributes columnalign right center left columnspacing 0px end attributes row cell integral subscript square root of 6 end subscript superscript 3 square root of 2 end superscript x square root of x squared minus 2 end root d x end cell equals cell open square brackets 1 third open parentheses x squared minus 2 close parentheses square root of x squared minus 2 end root close square brackets subscript square root of 6 end subscript superscript 3 square root of 2 end superscript end cell row blank equals cell open square brackets 1 third open parentheses open parentheses 3 square root of 2 close parentheses squared minus 2 close parentheses square root of open parentheses 3 square root of 2 close parentheses squared minus 2 end root close square brackets minus open square brackets 1 third open parentheses open parentheses square root of 6 close parentheses squared minus 2 close parentheses square root of open parentheses square root of 6 close parentheses squared minus 2 end root close square brackets end cell row blank equals cell 1 third open parentheses 16 close parentheses open parentheses 4 close parentheses minus 1 third open parentheses 4 close parentheses open parentheses 2 close parentheses end cell row blank equals cell 56 over 3 end cell row blank equals cell 18 2 over 3 end cell end table

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

14

Iklan

Pertanyaan serupa

Hasil dari ∫ x 3 − 1 ​ 4 x 2 ​ d x = ....

1

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2025 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia