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Nilai dari ∫ ( ( 54 x + 63 ) sin 3 ( 3 x 2 + 7 x − 1 ) . cos ( 3 x 2 + 7 x − 1 ) ) d x adalah...

Nilai dari adalah...

  1. 9 over 4 space sin to the power of 4 space open parentheses 3 x squared space plus space 7 x space minus space 1 close parentheses space plus space C

  2. sin to the power of 4 open parentheses 3 x squared space plus space 7 x space minus space 1 close parentheses space plus space C

  3. 9 space sin to the power of 4 space open parentheses 3 x squared space plus 7 x space minus space 1 close parentheses space plus space C

  4. 9 over 4 space sin cubed space open parentheses 3 x squared space plus space 7 x space plus space minus space 1 close parentheses space cos space open parentheses 3 x squared space plus 7 x space minus space 1 close parentheses space plus space C

  5. sin cubed space open parentheses 3 x squared space plus space 7 x space minus space 1 close parentheses space cos space open parentheses 3 x squared space plus space 7 x space minus space 1 close parentheses space plus space C

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Misalkan , maka Sehingga bentuk integral menjadi

integral space open parentheses open parentheses 54 x space plus space 63 close parentheses space sin cubed open parentheses 3 x squared space plus space 7 x space minus space 1 close parentheses. space cos space open parentheses 3 x squared space plus 7 x space minus space 1 close parentheses close parentheses space d x

Misalkan

u space equals space sin space open parentheses 3 x squared space plus space 7 x space minus space 1 close parentheses, maka

fraction numerator d u over denominator d x end fraction space equals space open parentheses 6 x space plus space 7 close parentheses space cos space open parentheses 3 x squared space plus 7 x space minus space 1 close parentheses d x space equals space fraction numerator d u over denominator open parentheses 6 x space plus space 7 close parentheses begin display style space end style begin display style cos end style begin display style space end style begin display style open parentheses 3 x squared space plus 7 x space minus space 1 close parentheses end style end fraction

Sehingga bentuk integral menjadi

integral open parentheses 9 open parentheses 6 x space plus space 7 close parentheses space u cubed space. space cos space open parentheses 3 x squared space plus space 7 x space minus space 1 close parentheses close parentheses fraction numerator d u over denominator open parentheses 6 x space plus space 7 close parentheses cos open parentheses 3 x squared space plus space 7 x space minus space 1 close parentheses end fraction integral 9 u cubed d u space equals space 9 over 4 u to the power of 4 space plus space C equals space 9 over 4 space sin to the power of 4 space open parentheses 3 x squared space plus space 7 x space minus space 1 close parentheses space plus space C

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