Roboguru

Nilai dari  adalah ....

Pertanyaan

Nilai dari begin mathsize 14px style open parentheses 2 to the power of 1 half end exponent close parentheses to the power of negative 4 end exponent plus open parentheses negative 4 close parentheses cubed cross times 16 to the power of negative 2 end exponent end style adalah ....       space 

  1. begin mathsize 14px style 0 end style   space 

  2. begin mathsize 14px style 1 over 8 end style   undefined 

  3. begin mathsize 14px style 1 fourth end style   undefined 

  4. begin mathsize 14px style 1 half end style   undefined 

Pembahasan Soal:

Dengan menggunakan sifat begin mathsize 14px style open parentheses a to the power of m close parentheses to the power of n equals a to the power of m cross times n end exponent end style dan begin mathsize 14px style a to the power of negative m end exponent equals 1 over a to the power of m end style 
Diperoleh 

begin mathsize 14px style open parentheses 2 to the power of 1 half end exponent close parentheses to the power of negative 4 end exponent equals 2 to the power of 1 half cross times negative 4 end exponent equals 2 to the power of negative 2 end exponent equals 1 over 2 squared equals 1 fourth end style 

begin mathsize 14px style open parentheses negative 4 close parentheses cubed equals negative 64 end style 

begin mathsize 14px style 16 to the power of negative 2 end exponent equals 1 over 16 squared equals 1 over 256 end style  

begin mathsize 14px style open parentheses 2 to the power of 1 half end exponent close parentheses to the power of negative 4 end exponent plus open parentheses negative 4 close parentheses cubed cross times 16 to the power of negative 2 end exponent equals 1 fourth plus open parentheses negative 64 close parentheses cross times 1 over 256 open parentheses 2 to the power of 1 half end exponent close parentheses to the power of negative 4 end exponent plus open parentheses negative 4 close parentheses cubed cross times 16 to the power of negative 2 end exponent equals 1 fourth plus open parentheses negative 1 fourth close parentheses equals 0 end style 

Jadi, nilainya adalah A. begin mathsize 14px style bold 0 end style           undefined 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 14 Maret 2021

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