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Pertanyaan

Nilai dari x → − 2 lim ​ x + 2 ​ x 2 + 7 x + 10 ​ = ....

Nilai dari ....

  1. -1

  2. 0

  3. 1

  4. square root of 2

  5. square root of 3

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N. Rahayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

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Pembahasan

limit as x rightwards arrow negative 2 of fraction numerator x squared plus 7 x plus 10 over denominator square root of x plus 2 end root end fraction equals limit as x rightwards arrow negative 2 of fraction numerator x squared plus 7 x plus 10 over denominator square root of x plus 2 end root end fraction space. fraction numerator square root of x plus 2 end root over denominator square root of x plus 2 end root end fraction equals limit as x rightwards arrow negative 2 of fraction numerator open parentheses x plus 2 close parentheses open parentheses x plus 5 close parentheses square root of x plus 2 end root over denominator open parentheses x plus 2 close parentheses end fraction space equals limit as x rightwards arrow negative 2 of open parentheses x plus 5 close parentheses square root of x plus 2 end root equals open parentheses open parentheses negative 2 close parentheses plus 5 close parentheses square root of negative 2 plus 2 end root equals 0

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