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Pertanyaan

Nilai x → 1 lim ​ 1 − x ( 5 − x ​ − 2 ) ( 2 − x ​ + 1 ) ​ adalah ...

Nilai  adalah ...

  1. negative 1 half

  2. negative 1 fourth

  3. 1 over 8

  4. 1 fourth

  5. 1 half

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N. Rahayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

limit as x rightwards arrow 1 of fraction numerator open parentheses square root of 5 minus x end root minus 2 close parentheses open parentheses square root of 2 minus x end root plus 1 close parentheses over denominator 1 minus x end fraction equals fraction numerator open parentheses square root of 5 minus 1 end root minus 2 close parentheses open parentheses square root of 2 minus 1 end root plus 1 close parentheses over denominator 1 minus 1 end fraction equals 0 over 0 comma space k a r e n a space h a s i ln y a space 0 over 0 space m a k a space b e n t u k space h a r u s d i r a s i o n a l k a n space d e n g a n space c a r a space m e n g a l i k a n space d e n g a n space s e k a w a n n y a comma space y a i t u space colon equals limit as x rightwards arrow 1 of fraction numerator open parentheses square root of 5 minus x end root minus 2 close parentheses open parentheses square root of 2 minus x end root plus 1 close parentheses over denominator 1 minus x end fraction cross times fraction numerator open parentheses square root of 5 minus x end root plus 2 close parentheses over denominator open parentheses square root of 5 minus x end root plus 2 close parentheses end fraction equals limit as x rightwards arrow 1 of fraction numerator open parentheses open parentheses 5 minus x close parentheses minus 4 close parentheses open parentheses square root of 2 minus x end root plus 1 close parentheses over denominator open parentheses 1 minus x close parentheses open parentheses square root of 5 minus x end root plus 2 close parentheses end fraction equals limit as x rightwards arrow 1 of fraction numerator open parentheses 1 minus x close parentheses open parentheses square root of 2 minus x end root plus 1 close parentheses over denominator open parentheses 1 minus x close parentheses open parentheses square root of 5 minus x end root plus 2 close parentheses end fraction equals limit as x rightwards arrow 1 of fraction numerator open parentheses square root of 2 minus x end root plus 1 close parentheses over denominator open parentheses square root of 5 minus x end root plus 2 close parentheses end fraction equals fraction numerator open parentheses square root of 2 minus 2 end root plus 1 close parentheses over denominator open parentheses square root of 5 minus 1 end root plus 2 close parentheses end fraction equals fraction numerator 1 plus 1 over denominator 2 plus 2 end fraction equals 1 half

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x → 5 lim ​ x ​ − 5 ​ x ​ ( x − 5 ) ​ = ...

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