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Misalkan x dan y adalah himpunan penyelesaian yang memenuhi sistem persamaan 5 x − 2 y + 1 = 2 5 x − 2 y dan 4 x − y + 2 = 3 2 x − 2 y + 1 , maka nilai xy adalah ...

Misalkan x dan y adalah himpunan penyelesaian yang memenuhi sistem persamaan  dan , maka nilai xy adalah ...

  1. 6

  2. 8

  3. 10

  4. 15

  5. 20

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Master Teacher

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Kemudian cari nilai x dan y dengan metode eliminasi

table attributes columnalign right center left columnspacing 0px end attributes row cell 5 to the power of x minus 2 y plus 1 end exponent end cell equals cell 25 to the power of x minus 2 y end exponent end cell row cell 5 to the power of x minus 2 y plus 1 end exponent end cell equals cell open parentheses 5 squared close parentheses to the power of x minus 2 y end exponent end cell row cell up diagonal strike 5 to the power of x minus 2 y plus 1 end exponent end cell equals cell up diagonal strike 5 to the power of 2 x minus 4 y end exponent end cell row cell x minus 2 y plus 1 end cell equals cell 2 x minus 4 y end cell row cell negative x plus 2 y end cell equals cell negative 1 space... space left parenthesis i right parenthesis end cell end table

 

table attributes columnalign right center left columnspacing 0px end attributes row cell 4 to the power of x minus y plus 2 end exponent end cell equals cell 32 to the power of x minus 2 y plus 1 end exponent end cell row cell open parentheses 2 squared close parentheses to the power of x minus y plus 2 end exponent end cell equals cell open parentheses 2 to the power of 5 close parentheses to the power of x minus 2 y plus 1 end exponent end cell row cell up diagonal strike 2 to the power of 2 x minus 2 y plus 4 end exponent end cell equals cell up diagonal strike 2 to the power of 5 x minus 10 y plus 5 end exponent end cell row cell 2 x minus 2 y plus 4 end cell equals cell 5 x minus 10 y plus 5 end cell row cell negative 3 x plus 8 y end cell equals cell 1 space... space left parenthesis i i right parenthesis end cell end table

 

Kemudian cari nilai x dan y dengan metode eliminasi

bottom enclose table row cell negative x plus 2 y equals negative 1 end cell row cell negative 3 x plus 8 y equals 1 end cell end table open parentheses table row cell cross times 3 end cell row cell cross times 1 end cell end table close parentheses stack table row cell negative 3 x plus 6 y equals negative 3 end cell row cell negative 3 x plus 8 y equals 1 end cell end table with _ below end enclose subscript minus space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space minus 2 y equals negative 4 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space y equals 2 Akibatnya space nilai space x equals 5 Sehingga space nilai space x y equals left parenthesis 5 right parenthesis left parenthesis 2 right parenthesis equals 10

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