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Massa kalium sianida, KCN, yang terlarut dalam 500 mL larutan agar diperoleh pH sebesar 9 + log 2 adalah.... (Ar K = 39 gram/mol; C = 12 gram/mol; dan N = 14 gram/mol, Ka HCN = 2 x 10 -5 )

Massa kalium sianida, KCN,  yang terlarut dalam 500 mL larutan agar diperoleh pH sebesar 9 + log 2 adalah.... (Ar K = 39 gram/mol; C = 12 gram/mol; dan N = 14 gram/mol, Ka HCN = 2 x 10-5)

  1. 1,30 gram

  2. 2,60 gram

  3. 3,25 gram

  4. 13,0 gram 

  5. 26,0 gram 

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M. Firdhaus

Master Teacher

Mahasiswa/Alumni Universitas Jember

Jawaban terverifikasi

Pembahasan

Diketahui: Volume Larutan = 500 mL = 0,5 L pH garam = 9 + log 2 Mr KCN = Ar K + Ar C + Ar N = 39 + 12 + 14 = 65 gram/mol Ka = 2 x 10 -5 Ditanya: Massa KCN ….? Dijawab: pOH = 14 - (9 + log 2) = 5 – log 2 [OH - ] = 2 x 10 -5

Diketahui:        Volume Larutan = 500 mL  = 0,5 L

                        pH garam = 9 + log 2

                        Mr KCN = Ar K + Ar C + Ar N = 39 + 12 + 14 = 65 gram/mol

                        Ka = 2 x 10-5

Ditanya: Massa KCN ….?

Dijawab:

pOH     = 14 - (9 + log 2) = 5 – log 2

[OH-]   = 2 x 10-5

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