Pertanyaan

Larutan penyangga berikut yang memiliki pH paling besar adalah....

0,1 M larutan CH₃COOH dan 0,5 M larutan CH₃COONa (Ka = )
0,1 M larutan NH₃ dan 0,1 M larutan NH₄Cl (Kb = )
0,2 M larutan HCN dan 0,1 M larutan KCN (Ka = )
0,5 M larutan CH₃COOH dan 0,1 M larutan CH₃COONa (Ka = )
0,1 M NH₄OH dan 0,5 M NH₄Cl (Kb = )

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R. Harmiasri

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

Pembahasan

1) 0,1 M larutan CH 3 COOH dan 0,5 M larutan CH 3 COONa 2)0,1 M larutan NH 3 dan 0,1 M larutan NH 4 Cl 3)0,5 M larutan CH 3 COOH dan 0,1 M larutan CH 3 COONa 4)0,1 M NH 4 OH dan 0,5 M NH 4 Cl Maka pH yang paling besar adalah pH campuran 0,1 M larutan . Jadi, jawaban yang tepat adalah B.

1) 0,1 M larutan CH₃COOH dan 0,5 M larutan CH₃COONa

$begin mathsize 12px style left square bracket H to the power of plus right square bracket space equals space K subscript a space x space fraction numerator left square bracket A s a m right square bracket over denominator left square bracket B a s a space K o n j u g a s i right square bracket end fraction left square bracket H to the power of plus right square bracket space equals space 1 space x space 10 to the power of negative 5 end exponent space x space fraction numerator 0 comma 1 space over denominator 0 comma 5 space end fraction left square bracket H to the power of plus right square bracket space equals space 2 space x space 10 to the power of negative 6 end exponent p H space equals space minus space log space left square bracket H to the power of plus right square bracket space p H space equals space minus space log space 2 space x space 10 to the power of negative 6 end exponent p H space equals space 6 space minus space log space 2 space space space end style$

2) 0,1 M larutan NH₃ dan 0,1 M larutan NH₄Cl

$begin mathsize 12px style left square bracket O H to the power of minus right square bracket space equals space K subscript b space x space fraction numerator left square bracket B a s a right square bracket over denominator left square bracket A s a m space K o n j u g a s i right square bracket end fraction left square bracket O H to the power of minus right square bracket space equals space 1 space x space 10 to the power of negative 5 end exponent space x space fraction numerator 0 comma 1 space over denominator 0 comma 1 space end fraction left square bracket O H to the power of minus right square bracket space equals space 1 space x space 10 to the power of negative 5 end exponent p O H space equals space minus space log space left square bracket O H to the power of minus right square bracket space p O H space equals space minus space log space 1 space x space 10 to the power of negative 5 end exponent p O H space equals space 5 space minus space log space 1 space left parenthesis log space 1 space equals space 0 right parenthesis space space end style$

3) 0,5 M larutan CH₃COOH dan 0,1 M larutan CH₃COONa

$begin mathsize 12px style left square bracket H to the power of plus right square bracket space equals space K subscript a space x space fraction numerator left square bracket C H subscript 3 C O O H right square bracket over denominator left square bracket C H subscript 3 C O O N a right square bracket end fraction left square bracket H to the power of plus right square bracket space equals space 1 space x space 10 to the power of negative 5 end exponent space x space fraction numerator 0 comma 5 space over denominator 0 comma 1 space end fraction left square bracket H to the power of plus right square bracket space equals space 5 space x space 10 to the power of negative 5 end exponent p H space equals space minus space log space left square bracket H to the power of plus right square bracket space p H space equals space minus space log space 5 space x space 10 to the power of negative 5 end exponent p H space equals space 5 space minus space log space 5 space end style$

4) 0,1 M NH₄OH dan 0,5 M NH₄Cl

$begin mathsize 12px style left square bracket O H to the power of minus right square bracket space equals space K subscript b space end subscript x space fraction numerator left square bracket N H subscript 4 O H right square bracket over denominator left square bracket N H subscript 4 C l right square bracket end fraction left square bracket O H to the power of minus right square bracket space equals space 1 space x space 10 to the power of negative 5 space end exponent x space fraction numerator 0 comma 1 space over denominator 0 comma 5 space end fraction left square bracket O H to the power of minus right square bracket space equals space 2 space x space 10 to the power of negative 6 end exponent p O H space equals space minus space log space left square bracket O H to the power of minus right square bracket p O H space equals space minus space log space 2 space x space 10 to the power of negative 6 end exponent p O H space equals space 6 space minus space log space 2 p H space equals space 14 space minus space p O H space p H space equals space 14 space minus space left parenthesis 6 space minus space log space 2 right parenthesis p H space equals space 8 space plus space log space 2 end style$

Maka pH yang paling besar adalah pH campuran 0,1 M larutan .

Jadi, jawaban yang tepat adalah B.

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