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Larutan mengandung 9% urea CO(NH 2 ) 2 dan 12% MgSO 4 dalam air. Kenaikan titik didih ( △ Tb) larutan tersebut adalah …… (Mr urea=60, Mr MgSO 4 =120, Kb air=0,52 0 C/m)

Larutan mengandung 9% urea CO(NH2)2 dan 12% MgSO4 dalam air. Kenaikan titik didih (Tb) larutan tersebut adalah …… (Mr urea=60, Mr MgSO4=120, Kb air=0,520C/m)

  1. 10,59

  2. 5,69

  3. 2,30

  4. 1,06

  5. 0,57

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R. RGFREELANCETIGASATU

Master Teacher

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Pembahasan

Diketahui: Massa Urea = 9% = 9 gram Massa MgSO 4 = 12% = 12 gram Mr Urea = 60 gram/mol Mr MgSO 4 = 120 gram/mol Kb = 0,52 0 C/m Ditanya: Tb….? Dijawab: MgSO 4 (aq) Mg +2 (aq) + SO 4 -2 (n = 2; maka i = 2) Massa air (pelarut) = 100 gram – (9 gram + 12 gram) = 79 gram

Diketahui:   Massa Urea = 9% = 9 gram

                   Massa MgSO4 = 12% = 12 gram

                   Mr Urea = 60 gram/mol

                   Mr MgSO4 = 120 gram/mol

                   Kb = 0,520C/m

Ditanya: incrementTb….?

Dijawab:

MgSO4 (aq) rightwards arrow Mg+2 (aq) + SO4-2    (n = 2; maka i = 2)

Massa air (pelarut) = 100 gram – (9 gram + 12 gram) = 79 gram

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