Roboguru

Larutan  dicampurkan ke dalam larutan . Jika pH campuran larutan tersebut sebesar , perbandingan volume larutan  dengan larutan  dalam campuran tersebut adalah ....

Pertanyaan

Larutan begin mathsize 14px style Na O H space 0 comma 01 space M end style dicampurkan ke dalam larutan begin mathsize 14px style Ba open parentheses O H close parentheses subscript 2 space 0 comma 01 space M end style. Jika pH campuran larutan tersebut sebesar begin mathsize 14px style 2 minus sign log 1 comma 5 end style, perbandingan volume larutan undefined dengan larutan undefined dalam campuran tersebut adalah ....space 

  1. begin mathsize 14px style 1 colon 4 end style undefined 

  2. begin mathsize 14px style 1 colon 2 end style undefined 

  3. begin mathsize 14px style 1 colon 1 end style undefined 

  4. begin mathsize 14px style 2 colon 1 end style space 

  5. begin mathsize 14px style 4 colon 1 end style undefined 

Pembahasan Soal:

Keduanya merupakan basa kuat yang pH campurannya tidak mungkin < dari 7, kemungkinan ada kesalahan pada soal dimana yang diketahui adalah pOH nya sebesar begin mathsize 14px style 2 minus sign log 1 comma 5 end style. Untuk mencari perbandingan volume campuran, diperoleh dari rumus begin mathsize 14px style open square brackets O H to the power of minus sign close square brackets end style campuran. 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row cell 2 minus sign log space 1 comma 5 end cell equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 1 comma 5 cross times 10 to the power of negative sign 2 end exponent end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets subscript 1 end cell equals cell b cross times M subscript b end cell row blank equals cell 1 cross times 0 comma 01 end cell row blank equals cell 10 to the power of negative sign 2 end exponent end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets subscript 2 end cell equals cell b cross times M subscript b end cell row blank equals cell 2 cross times 0 comma 01 end cell row blank equals cell 2 cross times 10 to the power of negative sign 2 end exponent end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets subscript camp end cell equals cell fraction numerator open square brackets O H to the power of minus sign close square brackets subscript 1 cross times V subscript 1 end subscript space plus open square brackets O H to the power of minus sign close square brackets subscript 2 cross times V subscript 2 space over denominator V subscript 1 and V subscript 2 end fraction space end cell row cell 1 comma 5 cross times 10 to the power of negative sign 2 end exponent end cell equals cell fraction numerator left parenthesis 10 to the power of negative sign 2 end exponent cross times V subscript 1 right parenthesis plus left parenthesis 2 cross times 10 to the power of negative sign 2 end exponent cross times V subscript 2 right parenthesis over denominator V subscript 1 and V subscript 2 end fraction end cell row cell 1 comma 5 cross times 10 to the power of negative sign 2 end exponent left parenthesis V subscript 1 and V subscript 2 right parenthesis end cell equals cell 10 to the power of negative sign 2 end exponent V subscript 1 plus 2 cross times 10 to the power of negative sign 2 end exponent V subscript 2 end cell row cell 1 comma 5 cross times 10 to the power of negative sign 2 end exponent V subscript 1 plus 1 comma 5 cross times 10 to the power of negative sign 2 end exponent V subscript 2 end cell equals cell 10 to the power of negative sign 2 end exponent V subscript 1 plus 2 cross times 10 to the power of negative sign 2 end exponent V subscript 2 end cell row cell 1 comma 5 cross times 10 to the power of negative sign 2 end exponent V subscript 1 minus sign 10 to the power of negative sign 2 end exponent V subscript 1 end cell equals cell 2 cross times 10 to the power of negative sign 2 end exponent V subscript 2 minus sign 1 comma 5 cross times 10 to the power of negative sign 2 end exponent V subscript 2 end cell row cell 0 comma 5 V subscript 1 end cell equals cell 0 comma 5 V subscript 2 end cell row cell V subscript 1 colon V subscript 2 end cell equals cell 1 colon 1 end cell end table end style  

 Jadi, jawaban yang benar adalah C.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 12 Februari 2021

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