Iklan

Pertanyaan

Kelarutan ion Ba 2+ (dalam mol/L) dalam suatu garam Ba 3 (PO 4 ) 2 1,31 gram (Mr = 262 g/mol) yang dilarutkan ke dalam 200 mL air adalah…

Kelarutan ion Ba2+ (dalam mol/L) dalam suatu garam Ba3(PO4)2 1,31 gram (Mr = 262 g/mol) yang dilarutkan ke dalam 200 mL air adalah…

  1. 7,5 x 10-4 M

  2. 7,5 x 10-3 M

  3. 75 x 10-2 M  

  4. 75 x 10-4 M

  5. 7,5 x 10-2 M

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

01

:

04

:

31

:

23

Klaim

Iklan

M. Firdhaus

Master Teacher

Mahasiswa/Alumni Universitas Jember

Jawaban terverifikasi

Jawaban

kelarutan ion Ba 2+ dalam garam Ba 3 ­(PO 4 ) 2 adalah 7,5 x 10 -2 mol/L

kelarutan ion Ba2+ dalam garam Ba3­(PO4)2 adalah 7,5 x 10-2 mol/L

Pembahasan

Sehingga kelarutan ion Ba 2+ dalam garam Ba 3 ­(PO 4 ) 2 adalah 7,5 x 10 -2 mol/L

Massa space Ba subscript 3 left parenthesis PO subscript 4 right parenthesis subscript 2 equals 1 comma 31 space gram Volume space equals 200 space ml straight M space Ba subscript 3 left parenthesis PO subscript 4 right parenthesis subscript 2 equals fraction numerator gram cross times 1000 over denominator Mr cross times volume end fraction straight M space Ba subscript 3 left parenthesis PO subscript 4 right parenthesis subscript 2 equals fraction numerator gram cross times 1000 over denominator Mr cross times volume end fraction straight M space Ba subscript 3 left parenthesis PO subscript 4 right parenthesis subscript 2 equals 2 comma 5 cross times 10 to the power of negative 2 end exponent space mol divided by straight L  Ba subscript 3 left parenthesis PO subscript 4 right parenthesis subscript 2 space space space space space space space space space space space space space space space space space space rightwards harpoon over leftwards harpoon space space space space space 3 Ba to the power of 2 plus end exponent space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space plus space space space space space space space space space space space space space space space space 2 PO subscript 4 to the power of 3 minus end exponent 2 comma 5 cross times 10 to the power of negative 2 end exponent space mol divided by straight L space space space space space space space space space space space space space space space space 3 cross times open parentheses 2 comma 5 cross times 10 to the power of negative 2 end exponent close parentheses mol divided by straight L space space space space space space space space space space space space space space space space space space space space space 2 cross times open parentheses 2 comma 5 cross times 10 to the power of negative 2 end exponent close parentheses mol divided by straight L space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 7 comma 5 cross times 10 to the power of negative 2 space end exponent mol divided by straight L space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 5 cross times 10 to the power of negative 2 end exponent space mol divided by straight L space space space space space space space space space space space space space space space space space

Sehingga kelarutan ion Ba2+ dalam garam Ba3­(PO4)2 adalah 7,5 x 10-2 mol/L

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Pertanyaan serupa

Larutan jenuh CaF 2 ​ sebanyak 500 ml air mengandung (Ar Ca = 40, F = 19) ion flourin sebesar .Jumlah garam dalam larutan adalah ….

2

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2026 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia