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Ke dalam 10 mL CH 3 ​ COOH 0 , 1 M ditambahkan 10 mL KOH yang mempunyai pH = 13 - log 2. K a ​ asam asetat = 1 0 − 5 . pH sebelum dan sesudah reaksi adalah ....

Ke dalam 10 mL  ditambahkan  yang mempunyai pH = 13 - log 2.  asam asetat = . pH sebelum dan sesudah reaksi adalah .... 

  1. 1 menjadi 5space 

  2. 1 menjadi 4 – log 5space 

  3. 1 menjadi 5 – log 4space 

  4. 3 menjadi 5space 

  5. 3 menjadi 5 - log 4space 

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Jawaban

jawaban yang benar adalah D.

jawaban yang benar adalah D.

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Langkah-langkah perhitungan pH dengan konsep penyangga: pH sebelum reaksi adalah pH , yaitu: pH sesudah reaksi adalah: Perubahan pH sebelum dan sesudah raksi adalah dari 3 menjadi 5. Jadi, jawaban yang benar adalah D.

Langkah-langkah perhitungan pH dengan konsep penyangga:

pH sebelum reaksi adalah pH begin mathsize 14px style C H subscript 3 C O O H end style, yaitu:

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of K subscript a point open square brackets C H subscript 3 C O O H close square brackets end root end cell row cell space space space space space space space end cell equals cell square root of 10 to the power of negative sign 5 end exponent.0 comma 1 end root end cell row cell space space space space space space space end cell equals cell square root of 10 to the power of negative sign 6 end exponent end root end cell row cell space space space space space space space end cell equals cell 10 to the power of negative sign 3 end exponent space M end cell row blank blank blank end table 

table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell negative log left square bracket straight H to the power of plus right square bracket end cell row cell space space space space space end cell equals cell negative log left parenthesis 10 to the power of negative 3 end exponent right parenthesis end cell row cell space space space space space end cell equals 3 end table

pH sesudah reaksi adalah:

table attributes columnalign right center left columnspacing 0px end attributes row cell pH space K O H end cell equals cell 13 – log space 2 end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 2 cross times 10 to the power of negative sign 13 end exponent space end cell row blank blank blank row cell open square brackets O H to the power of minus sign close square brackets open square brackets H to the power of plus sign close square brackets end cell equals cell 10 to the power of negative sign 14 end exponent end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell fraction numerator 10 to the power of negative sign 14 end exponent over denominator 2 cross times 10 to the power of negative sign 13 end exponent end fraction end cell row cell space space space space space space space end cell equals cell 5 cross times 10 to the power of negative sign 2 end exponent space M end cell row blank blank blank row cell M space K O H end cell equals cell M space open square brackets O H to the power of minus sign close square brackets end cell row cell space space space space space space space space space space space end cell equals cell 5 cross times 10 to the power of negative sign 2 end exponent space M end cell row blank equals cell 0 comma 05 space space M end cell row blank blank blank row cell n space K O H end cell equals cell M space K O H space cross times space V space K O H end cell row cell space space space space space space space space space space end cell equals cell 0 comma 05 space M point 10 space mL end cell row cell space space space space space space space space space space end cell equals cell 0 comma 5 space mmol space end cell row blank blank blank row cell n space C H subscript 3 C O O H end cell equals cell n space C H subscript 3 C O O H space cross times space V C H subscript 3 C O O H end cell row cell space space space space space space space space space space space space space space space space space space space space end cell equals cell 0 comma 1 space M point 10 mL end cell row cell space space space space space space space space space space space space space space space space space space space space end cell equals cell 1 space mmol end cell end table   
 

 

n space C H subscript 3 C O O H equals 0 comma 5 space mmol n space C H subscript 3 C O O to the power of minus sign equals 0 comma 5 space mmol space

table attributes columnalign right center left columnspacing 0px end attributes row cell left square bracket straight H to the power of plus right square bracket end cell equals cell straight K subscript straight a cross times fraction numerator straight n space space CH subscript 3 COOH space over denominator straight n space CH subscript 3 COO to the power of minus end fraction end cell row cell space space space space space space space end cell equals cell 10 to the power of negative 5 end exponent cross times fraction numerator 0 comma 5 over denominator 0 comma 5 end fraction end cell row blank equals cell 10 to the power of negative 5 end exponent space straight M end cell row blank blank blank end table

table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell negative log left square bracket straight H to the power of plus right square bracket end cell row cell space space space space space end cell equals cell negative log left parenthesis 10 to the power of negative 5 end exponent right parenthesis end cell row cell space space space space space end cell equals 5 end table 

Perubahan pH sebelum dan sesudah raksi adalah dari 3 menjadi 5.

Jadi, jawaban yang benar adalah D.

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