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Pertanyaan

Kalsium dan magnesium dapat mengendap sebagai hidroksida, dalam suatu sampel mengandung 0,01 M Ca 2 + dan 0,001 M Mg 2 + . Pada pH berapa, masing-masingion tersebut mulai mengendap ?

Kalsium dan magnesium dapat mengendap sebagai hidroksida, dalam suatu sampel mengandung 0,01 M dan 0,001 M . Pada pH berapa, masing-masing ion tersebut mulai mengendap ?

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N. Puspita

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Jawaban

ion mulai mengendap pada pH 12 log 2,2 sedangkan ion mulai mengendap pada pH 9 log7,5.

ion Ca to the power of 2 plus signmulai mengendap pada pH 12pluslog 2,2 sedangkan ion Mg to the power of 2 plus signmulai mengendap pada pH 9pluslog7,5.

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Pembahasan

Pembahasan

Soal perlu dilengkapi dengan data Ksp. Pada suhu 25 dan tekanan 1 atm, Ksp dan . pH pada saat mulai mengendap : Syarat agar mulai mengendap , maka : pH pada saat mulai mengendap : Syarat agar mulai mengendap , maka : Jadi, ion mulai mengendap pada pH 12 log 2,2 sedangkan ion mulai mengendap pada pH 9 log7,5.

Soal perlu dilengkapi dengan data Ksp. Pada suhu 25 undefined dan tekanan 1 atm, Ksp begin mathsize 14px style Mg open parentheses O H close parentheses subscript 2 equals 5 comma 6 cross times 10 to the power of negative sign 12 end exponent end style dan K subscript sp begin mathsize 14px style Ca open parentheses O H close parentheses subscript 2 equals 5 comma 0 cross times 10 to the power of negative sign 6 end exponent end style

  • pH pada saat begin mathsize 14px style Ca open parentheses O H close parentheses subscript 2 end style mulai mengendap :

Ca open parentheses O H close parentheses subscript 2 equilibrium Ca to the power of 2 plus sign and 2 O H to the power of minus sign Q subscript sp space end subscript double bond open square brackets Ca to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared space  

Syarat agar mulai mengendap Q subscript sp double bond K subscript sp, maka :

table attributes columnalign right center left columnspacing 0px end attributes row cell Q subscript sp space Ca open parentheses O H close parentheses subscript 2 end cell equals cell K subscript sp space left parenthesis Ca open parentheses O H close parentheses subscript 2 comma space maka space space open square brackets Ca to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared equals 5 comma 0 cross times 10 to the power of negative sign 6 end exponent end cell row cell left square bracket 10 to the power of negative sign 2 end exponent right square bracket open square brackets O H to the power of minus sign close square brackets squared end cell equals cell 5 comma 0 cross times 10 to the power of negative sign 6 end exponent end cell row cell left square bracket O H minus sign right square bracket end cell equals cell square root of fraction numerator 5 comma 0 cross times 10 to the power of negative sign 6 end exponent over denominator 10 to the power of negative sign 2 end exponent end fraction end root end cell row cell left square bracket O H minus sign right square bracket end cell equals cell 2 comma 2 cross times 10 to the power of negative sign 2 end exponent end cell row blank blank blank end table
table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell negative sign log open square brackets O H to the power of minus sign close square brackets end cell row blank equals cell 2 minus sign log space 2 comma 2 end cell row blank blank blank row pH equals cell 14 minus sign pOH end cell row blank equals cell 14 minus sign left parenthesis 2 minus sign log space 2 comma 2 right parenthesis end cell row blank equals cell 12 plus log space 2 comma 2 end cell end table 
 

  •   pH pada saat Mg open parentheses O H close parentheses subscript 2 mulai mengendap :

Mg open parentheses O H close parentheses subscript 2 equilibrium Mg to the power of 2 plus sign and 2 O H to the power of minus sign Q subscript sp double bond open square brackets Mg to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared space 

Syarat agar mulai mengendap Q subscript sp double bond K subscript sp, maka :

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets Mg to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared end cell equals cell 5 comma 6 cross times 10 to the power of negative sign 12 end exponent end cell row cell left square bracket 10 to the power of negative sign 3 end exponent right square bracket left square bracket O H to the power of minus sign right square bracket squared end cell equals cell 5 comma 6 cross times 10 to the power of negative sign 12 end exponent end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of fraction numerator 5 comma 6 cross times 10 to the power of negative sign 12 end exponent over denominator 10 to the power of negative sign 3 end exponent end fraction end root end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 7 comma 5 cross times 10 to the power of negative sign 5 end exponent end cell row blank blank blank row blank blank blank end table 
table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell negative sign log open square brackets O H to the power of minus sign close square brackets end cell row blank equals cell 5 minus sign log space 7 comma 5 end cell row blank blank blank row pH equals cell 14 minus sign left parenthesis 5 minus sign log space 7 comma 5 right parenthesis end cell row blank equals cell 9 plus log space 7 comma 5 end cell end table 


Jadi, ion Ca to the power of 2 plus signmulai mengendap pada pH 12pluslog 2,2 sedangkan ion Mg to the power of 2 plus signmulai mengendap pada pH 9pluslog7,5.

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