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Kalium superoksida () digunakan dalam sistem penyangga hidup karena menyerap  dan membebaskan oksigen menurut reaksi berikut.    (belum setara)  a. Berapa mol oksigen dibebaskan jika 110 gram   direaksikan dengan  berlebih?  b. Berapa molekul oksigen dihasilkan untuk tiap mg  yang digunakan?

Pertanyaan

Kalium superoksida (K O subscript 2) digunakan dalam sistem penyangga hidup karena menyerap C O subscript 2 dan membebaskan oksigen menurut reaksi berikut. 

K O subscript 2 open parentheses italic s close parentheses space plus space C O subscript 2 open parentheses italic g close parentheses space rightwards arrow space K subscript 2 C O subscript 3 open parentheses italic s close parentheses space plus space O subscript 2 open parentheses italic g close parentheses  (belum setara) 

a. Berapa mol oksigen dibebaskan jika 110 gram C O subscript 2  direaksikan dengan K O subscript 2 berlebih? 

b. Berapa molekul oksigen dihasilkan untuk tiap mg K O subscript 2 yang digunakan?

Pembahasan Soal:

Persamaan reaksi setara:

4 K O subscript 2 open parentheses italic s close parentheses space plus space 2 C O subscript 2 open parentheses italic g close parentheses space rightwards arrow space 2 K subscript 2 C O subscript 3 open parentheses italic s close parentheses space plus space 3 O subscript 2 open parentheses italic g close parentheses 

a. Mol oksigen dibebaskan

table attributes columnalign right center left columnspacing 0px end attributes row cell italic n subscript O subscript bold 2 end subscript end cell equals cell fraction numerator Koef space O subscript 2 over denominator Koef space C O subscript 2 end fraction cross times n subscript C O subscript 2 end subscript end cell row blank equals cell 3 over 2 cross times 110 over 44 end cell row blank equals cell bold 3 bold comma bold 75 bold space bold mol end cell end table 

b. Jumlah molekul oksigen

table attributes columnalign right center left columnspacing 0px end attributes row cell bold Jumlah bold space bold Molekul bold space O subscript bold 2 end cell equals cell n cross times 6 comma 02 cross times 10 to the power of 23 end cell row blank equals cell 3 comma 75 cross times 6 comma 02 cross times 10 to the power of 23 end cell row blank equals cell bold 22 bold comma bold 6 bold cross times bold 10 to the power of bold 23 bold space bold molekul end cell end table 

Jadi, jawaban yang benar sesuai penjelasan diatas.

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

A. Chandra

Mahasiswa/Alumni Universitas Negeri Jakarta

Terakhir diupdate 01 Mei 2021

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Pertanyaan yang serupa

Lengkapi tabel berikut ini!

Pembahasan Soal:

Langkah 1: Melengkapi tabel NO

1. Mol NO (n)

    table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript NO end cell equals cell fraction numerator jumlah space partikel subscript NO over denominator L end fraction end cell row blank equals cell fraction numerator 6 comma 02 cross times 10 to the power of 23 space over denominator 6 comma 022 cross times 10 to the power of 23 end fraction end cell row blank equals cell 1 space mol end cell end table


2. Mr NO 

    table attributes columnalign right center left columnspacing 0px end attributes row cell Mr subscript NO end cell equals cell Ar subscript N and Ar subscript O end cell row blank equals cell 14 plus 16 end cell row blank equals cell 30 space begin inline style bevelled gram over mol end style end cell end table


3. Massa NO (m)

    table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript NO end cell equals cell n subscript NO cross times Mr subscript NO end cell row blank equals cell 1 space mol space cross times 30 space begin inline style bevelled gram over mol end style end cell row blank equals cell 30 space gram end cell end table


4. Volume NO (STP)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript NO end cell equals cell n subscript NO cross times 22 comma 4 space begin inline style bevelled L over mol end style end cell row blank equals cell 1 space mol space cross times 22 comma 4 space begin inline style bevelled L over mol end style end cell row blank equals cell 22 comma 4 space L end cell end table


5. Volume NO (27bold degree bold space C, 1 atm)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript NO end cell equals cell n subscript NO cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 1 space mol cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 24 space L end cell end table


Langkah 2: Melangkapi tabel H subscript bold 2 

1. Jumlah partikel H subscript bold 2 (x)

    table attributes columnalign right center left columnspacing 0px end attributes row cell Jumlah space partikel subscript H subscript 2 end subscript end cell equals cell n subscript H subscript 2 end subscript cross times L end cell row blank equals cell 0 comma 1 space mol cross times 6 comma 022 cross times 10 to the power of 23 space partikel end cell row blank equals cell 6 comma 022 cross times 10 to the power of 22 space partikel end cell row blank blank blank end table

2. Mr H subscript bold 2

    table attributes columnalign right center left columnspacing 0px end attributes row cell Mr subscript H subscript 2 end subscript end cell equals cell 2 cross times Ar subscript H end cell row blank equals cell 2 cross times 1 space begin inline style bevelled gram over mol end style end cell row blank equals cell 2 space begin inline style bevelled gram over mol end style end cell end table
 

3. Massa H subscript bold 2

    table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript H subscript 2 end subscript end cell equals cell n subscript H subscript 2 end subscript cross times Mr subscript H subscript 2 end subscript end cell row blank equals cell 0 comma 1 space mol space cross times 2 space begin inline style bevelled gram over mol end style end cell row blank equals cell 0 comma 2 space gram end cell end table


4. Volume H subscript bold 2 (STP)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript H subscript 2 end subscript end cell equals cell n subscript H subscript 2 end subscript cross times 22 comma 4 space begin inline style bevelled L over mol end style end cell row blank equals cell 0 comma 1 space mol space cross times 22 comma 4 space begin inline style bevelled L over mol end style end cell row blank equals cell 2 comma 24 space L end cell end table


5. Volume H subscript bold 2 (27bold degree bold space C, 1 atm)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript H subscript 2 end subscript end cell equals cell n subscript H subscript 2 end subscript cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 0 comma 1 space mol cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 2 comma 4 space L end cell end table


Langkah 3: Melangkapi tabel N H subscript bold 3

1. mol N H subscript bold 3 (n)

    table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript N H subscript 3 end subscript end cell equals cell fraction numerator V subscript STP subscript N H subscript 3 end subscript end subscript over denominator 22 comma 4 space bevelled L over mol end fraction end cell row blank equals cell fraction numerator 4 comma 48 space L over denominator 22 comma 4 space bevelled L over mol end fraction end cell row blank equals cell 0 comma 2 space mol end cell end table
 

2. Jumlah partikel N H subscript bold 3 (x)
     table attributes columnalign right center left columnspacing 0px end attributes row cell Jumlah space partikel subscript N H subscript 3 end subscript end cell equals cell n subscript N H subscript 3 end subscript cross times L end cell row blank equals cell 0 comma 2 space mol cross times 6 comma 022 cross times 10 to the power of 23 space partikel end cell row blank equals cell 1 comma 2 cross times 10 to the power of 23 space partikel end cell end table


3. Mr N H subscript bold 3

    table attributes columnalign right center left columnspacing 0px end attributes row cell Mr subscript N H subscript 3 end subscript end cell equals cell Ar subscript N plus left parenthesis 3 cross times Ar subscript H right parenthesis end cell row blank equals cell 14 space begin inline style bevelled gram over mol end style plus left parenthesis 3 cross times 1 space begin inline style bevelled gram over mol right parenthesis end style end cell row blank equals cell 17 space begin inline style bevelled gram over mol end style end cell end table
 

4. Massa N H subscript bold 3

    table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript N H subscript 3 end subscript end cell equals cell n subscript N H subscript 3 end subscript cross times Mr subscript N H subscript 3 end subscript end cell row blank equals cell 0 comma 2 space mol space cross times 17 space begin inline style bevelled gram over mol end style end cell row blank equals cell 3 comma 4 space gram end cell end table


5. Volume N H subscript bold 3 (27bold degree bold space C, 1 atm)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript N H subscript 3 end subscript end cell equals cell n subscript N H subscript 3 end subscript cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 0 comma 2 space mol cross times 24 space begin inline style bevelled L over mol end style end cell row blank equals cell 4 comma 8 space L end cell end table


Langkah 4: Melangkapi tabel C H subscript 4

1. mol C H subscript 4 (n)

    table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript C H subscript 4 end subscript end cell equals cell fraction numerator V subscript RTP subscript C H subscript 4 end subscript end subscript over denominator 24 space bevelled L over mol end fraction end cell row blank equals cell fraction numerator 12 comma 3 space L over denominator 24 space bevelled L over mol end fraction end cell row blank equals cell 0 comma 5125 space mol end cell end table 
 

2. Jumlah partikel C H subscript 4 (x)
     table attributes columnalign right center left columnspacing 0px end attributes row cell Jumlah space partikel subscript C H subscript 4 end subscript end cell equals cell n subscript C H subscript 4 end subscript cross times L end cell row blank equals cell 0 comma 512 space mol cross times 6 comma 022 cross times 10 to the power of 23 space partikel end cell row blank equals cell 3 comma 08 cross times 10 to the power of 23 space partikel end cell end table


3. Mr C H subscript 4

    table attributes columnalign right center left columnspacing 0px end attributes row cell Mr subscript C H subscript 4 end subscript end cell equals cell Ar subscript C plus left parenthesis 4 cross times Ar subscript H right parenthesis end cell row blank equals cell 12 space begin inline style bevelled gram over mol end style plus left parenthesis 4 cross times 1 space begin inline style bevelled gram over mol right parenthesis end style end cell row blank equals cell 16 space begin inline style bevelled gram over mol end style end cell end table
 

4. Massa C H subscript 4

    table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript C H subscript 4 end subscript end cell equals cell n subscript C H subscript 4 end subscript cross times Mr subscript C H subscript 4 end subscript end cell row blank equals cell 0 comma 512 space mol space cross times 16 space begin inline style bevelled gram over mol end style end cell row blank equals cell 8 comma 2 space gram end cell end table 


5. Volume C H subscript 4 (STP)

    table attributes columnalign right center left columnspacing 0px end attributes row cell V subscript C H subscript 4 end subscript end cell equals cell n subscript C H subscript 4 end subscript cross times 22 comma 4 space begin inline style bevelled L over mol end style end cell row blank equals cell 0 comma 512 space mol cross times 22.4 space begin inline style bevelled L over mol end style end cell row blank equals cell 11 comma 48 space L end cell end table  


Dengan demikian, tabel lengkapnya adalah

0

Roboguru

Jumlah molekul yang terdapat di dalam 2,56 gram kristal belerang () adalah....

Pembahasan Soal:

Jawaban : E

Pembahasan :

Mol S8 = fraction numerator m a s s a over denominator M r end fraction equals fraction numerator 2 comma 56 space g r over denominator 256 space g r divided by m o l end fraction equals 0 comma 01 space m o l

Jumlah molekul = mol x bilangan Avogadro = 0,01 mol x 6,02 x 1023 molekul S8

0

Roboguru

Massa molar CO adalah 28 gram/mol, maka massa molekul CO adalah....

Pembahasan Soal:

Jawaban : B

Pembahasan

Mol CO = fraction numerator j u m l a h space p a r t i k e l over denominator b i l a n g a n space a v o g a d r o end fraction equals fraction numerator 3 comma 01 space x space 10 to the power of 24 over denominator 6 comma 02 space x space 10 to the power of 23 end fraction equals 5 space m o l

Massa CO = Mol x Mr CO = 5 mol x 28 gr/mol = 140 gr

0

Roboguru

Lengkapi tabel dibawah ini, bila diketahui Ar P = 31, Ca = 40, O = 16, Zn = 65, N = 14, Mg = 24, K = 39, Cr = 52, Mn = 55. Ditulis pembahasan perhitungannya.

Pembahasan Soal:

Tabel di atas dapat dilengkapi dengan konversi antar satuan dengan jumlah mol.

begin mathsize 14px style Ca subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row Mr equals cell ΣAr space Ca subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 equals 3 cross times Ca plus 2 cross times P plus 2 cross times 4 cross times O end cell row blank equals cell 3 cross times 40 plus 2 cross times 31 plus 2 cross times 4 cross times 16 end cell row blank equals cell 120 plus 62 plus 128 end cell row blank equals 310 end table end style 

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row Massa equals cell n cross times Mr end cell row blank equals cell 0 comma 4 cross times 310 end cell row blank equals cell 124 space g end cell end table end style 

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row X equals cell n cross times 6 comma 02 cross times 10 to the power of 23 end cell row blank equals cell 0 comma 4 cross times 6 comma 02 cross times 10 to the power of 23 end cell row blank equals cell 2 comma 408 cross times 10 to the power of 23 end cell end table end style 

V tidak dapat dicari, karena keadaan (T dan p) tidak diketahui.


begin mathsize 14px style Zn open parentheses N O subscript 3 close parentheses subscript 2 end style 

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row Mr equals cell ΣAr space Zn open parentheses N O subscript 3 close parentheses subscript 2 equals Zn plus 2 cross times N plus 2 cross times 3 cross times O end cell row blank equals cell 65 plus 2 cross times 14 plus 2 cross times 3 cross times 16 end cell row blank equals cell 65 plus 28 plus 96 end cell row blank equals 189 end table end style 

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row n equals cell massa over M subscript r end cell row blank equals cell fraction numerator 60 space g over denominator 189 space g forward slash mol end fraction end cell row blank equals cell 0 comma 32 space mol end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row X equals cell n cross times 6 comma 02 cross times 10 to the power of 23 end cell row blank equals cell 0 comma 32 cross times 6 comma 02 cross times 10 to the power of 23 end cell row blank equals cell 1 comma 9264 cross times 10 to the power of 23 end cell end table end style 

V tidak dapat dicari, karena keadaan (T dan p) tidak diketahui.


begin mathsize 14px style Mg subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row Mr equals cell ΣAr space Mg subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 equals 3 cross times Mg plus 2 cross times P plus 2 cross times 4 cross times O end cell row blank equals cell 3 cross times 24 plus 2 cross times 31 plus 2 cross times 4 cross times 16 end cell row blank equals cell 72 plus 62 plus 128 end cell row blank equals 262 end table end style 

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row Massa equals cell n cross times Mr end cell row blank equals cell 0 comma 2 cross times 262 end cell row blank equals cell 52 comma 4 space g end cell end table end style 

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row X equals cell n cross times 6 comma 02 cross times 10 to the power of 23 end cell row blank equals cell 0 comma 2 cross times 6 comma 02 cross times 10 to the power of 23 end cell row blank equals cell 1 comma 204 cross times 10 to the power of 23 end cell end table end style 

V tidak dapat dicari, karena keadaan (T dan p) tidak diketahui.


begin mathsize 14px style K subscript 2 Cr subscript 2 O subscript 7 end style 

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row Mr equals cell ΣAr space K subscript 2 Cr subscript 2 O subscript 7 end cell row blank equals cell 2 cross times K plus 2 cross times Cr plus 7 cross times O end cell row blank equals cell 3 cross times 39 plus 2 cross times 52 plus 7 cross times 16 end cell row blank equals cell 117 plus 104 plus 112 end cell row blank equals 333 end table end style 

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row Massa equals cell n cross times Mr end cell row blank equals cell 0 comma 5 cross times 333 end cell row blank equals cell 166 comma 5 space g end cell end table end style 

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row X equals cell n cross times 6 comma 02 cross times 10 to the power of 23 end cell row blank equals cell 0 comma 5 cross times 6 comma 02 cross times 10 to the power of 23 end cell row blank equals cell 3 comma 01 cross times 10 to the power of 23 end cell end table end style 

V tidak dapat dicari, karena keadaan (T dan p) tidak diketahui.


begin mathsize 14px style K Mn O subscript 4 end style 

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row Mr equals cell ΣAr space K Mn O subscript 4 end cell row blank equals cell K and Mn plus 4 cross times O end cell row blank equals cell 39 plus 55 plus 4 cross times 16 end cell row blank equals cell 39 plus 55 plus 64 end cell row blank equals 158 end table end style 

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row n equals cell massa over M subscript r end cell row blank equals cell fraction numerator 25 space g over denominator 158 space g forward slash mol end fraction end cell row blank equals cell 0 comma 16 space mol end cell end table end style 

 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row X equals cell n cross times 6 comma 02 cross times 10 to the power of 23 end cell row blank equals cell 0 comma 16 cross times 6 comma 02 cross times 10 to the power of 23 end cell row blank equals cell 0 comma 9632 cross times 10 to the power of 23 end cell row blank equals cell 9 comma 632 cross times 10 to the power of 23 end cell end table end style 

V tidak dapat dicari, karena keadaan (T dan p) tidak diketahui.

Maka tabel lengkapnya adalah sebagai berikut.


Jadi, data lengkap senyawa-senyawa tersebut adalah seperti pada tabel di atas.
 

0

Roboguru

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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