Pertanyaan

Jika massa 1 atom C-12 = a gr, Massa atom relatif ( A r ) dari N dan O berturut- turut adalah b sma dan c sma, berapakah massa 10 molekul gas nitrogen dioksida?

Jika massa 1 atom C-12 = a gr, Massa atom relatif ( $A_{r}$ ) dari N dan O berturut- turut adalah b sma dan c sma, berapakah massa 10 molekul gas nitrogen dioksida? $\;$

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Habis dalam

Klaim

A. Chandra

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Jawaban

massa yang benar adalah .

massa

begin mathsize 14px style N O subscript bold 2 end style

yang benar adalah $begin mathsize 14px style fraction numerator bold 19 bold comma bold 92 bold left parenthesis italic b bold plus bold 2 italic c bold right parenthesis over denominator italic a end fraction bold cross times bold 10 to the power of bold minus sign bold 23 end exponent bold space bold gram end style$ .

Pembahasan

Menentukan unsur: Menentukan : Menentukan massa : Jadi, massa yang benar adalah .

Menentukan begin mathsize 14px style italic A subscript r end style unsur:

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic A subscript r subscript N end cell equals cell fraction numerator m subscript N over denominator 1 over 12 cross times m subscript C minus sign 12 end subscript end fraction end cell row blank equals cell fraction numerator b over denominator 1 over 12 cross times a end fraction end cell row blank equals cell fraction numerator 12 b over denominator a end fraction end cell end table end style$

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic A subscript r subscript O end cell equals cell fraction numerator m subscript O over denominator 1 over 12 cross times m subscript C minus sign 12 end subscript end fraction end cell row blank equals cell fraction numerator c over denominator 1 over 12 cross times a end fraction end cell row blank equals cell fraction numerator 12 c over denominator a end fraction end cell end table end style$

Menentukan begin mathsize 14px style italic M subscript r space N O subscript 2 end style :

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r subscript N O subscript 2 end subscript end subscript end cell equals cell left parenthesis 1 cross times Ar space N right parenthesis plus left parenthesis 2 cross times Ar space O right parenthesis end cell row blank equals cell left parenthesis 1 cross times fraction numerator 12 b over denominator a end fraction right parenthesis plus left parenthesis 2 cross times fraction numerator 12 c over denominator a end fraction right parenthesis end cell row blank equals cell fraction numerator 12 b over denominator a end fraction plus fraction numerator 24 c over denominator a end fraction end cell row blank equals cell fraction numerator 12 left parenthesis b and 2 c right parenthesis over denominator a end fraction end cell end table end style$

Menentukan massa begin mathsize 14px style N O subscript 2 end style :

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row n equals cell fraction numerator jumlah space molekul over denominator 6 comma 02 cross times 10 to the power of 23 end fraction end cell row blank equals cell fraction numerator 10 over denominator 6 comma 02 cross times 10 to the power of 23 end fraction end cell row blank equals cell 1 comma 66 cross times 10 to the power of negative sign 23 end exponent end cell end table end style$

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript N O subscript 2 end subscript end cell equals cell n cross times Mr end cell row blank equals cell 1 comma 66 cross times 10 to the power of negative sign 23 end exponent cross times fraction numerator 12 left parenthesis b and 2 c right parenthesis over denominator a end fraction end cell row blank equals cell fraction numerator 19 comma 92 left parenthesis b and 2 c right parenthesis over denominator a end fraction cross times 10 to the power of negative sign 23 end exponent space gram end cell end table end style$

Jadi, massa yang benar adalah $begin mathsize 14px style fraction numerator bold 19 bold comma bold 92 bold left parenthesis italic b bold plus bold 2 italic c bold right parenthesis over denominator italic a end fraction bold cross times bold 10 to the power of bold minus sign bold 23 end exponent bold space bold gram end style$ .