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Pertanyaan

Jika lo g x + lo g 2 x + lo g x + lo g 8 x + ... + lo g 1024 x = 22 , maka x = ….

Jika , maka x = ….

  1. 5,5
     

  2. 3,125

     

  3. 2,75
     

  4. 1,375
     

  5. 0,625

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N. Rahayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

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Pembahasan

Deret 1+ 2 + … + 10 memiliki a = 1 dan b = 2 – 1 = 1 Sehingga Maka persamaan logaritmanya menjadi : maka .

log space straight x space plus space log space 2 straight x space plus space log space 4 straight x space plus space log space 8 straight x space plus space... space plus space log space 1024 straight x equals 22 log space straight x space plus space log space 2 straight x space plus space log space 2 squared straight x space plus space log space 2 cubed straight x space plus space... space plus space log space 2 to the power of 10 straight x equals 22 log space open parentheses straight x to the power of 11 2 to the power of 1 plus 2 plus... plus 10 end exponent close parentheses equals 22

Deret 1+ 2 + … + 10  memiliki a = 1 dan b = 2 – 1 = 1
Sehingga straight S subscript 10 equals 10 over 2 open parentheses 2.1 plus open parentheses 10 minus 1 close parentheses 1 close parentheses equals 55
Maka persamaan logaritmanya menjadi :
log space open parentheses straight x to the power of 11 times 2 to the power of 55 close parentheses equals 22 space log space open parentheses straight x times 2 to the power of 5 close parentheses to the power of 11 equals 22 space 11 space log space space open parentheses straight x times 2 to the power of 5 close parentheses equals 22 log space 32 x equals 2 left right arrow 32 x equals 10 squared

maka 32 straight x space equals space 100 rightwards arrow straight x space equals space 3 comma 125.

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Diketahui 3 lo g a 2 b 3 lo g b 2 a ​ ​ = = ​ 4 − 3 ​ Maka a − b ​ = … + 3 m u .

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