Pertanyaan

Jika m = 0,8333…, n = 0,66666…., dan a = 256, maka nilai dari ( a − 2 a n ) n − 2 x ( a − 2 a n ) n − 2 x ( a n a − 2 ) n − 2 adalah ….

Jika m = 0,8333…, n = 0,66666…., dan a = 256, maka nilai dari $(\frac{a ^{n}}{a ^{- 2}})^{n - 2} x (\frac{a ^{n}}{a ^{- 2}})^{n - 2} x (\frac{a - 2}{a ^{n}})^{n - 2}$ adalah ….

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Habis dalam

Klaim

L. Indah

Master Teacher

Mahasiswa/Alumni Universitas Siliwangi

Jawaban terverifikasi

Jawaban

nilai dari

nilai dari $open parentheses a to the power of n over a to the power of negative 2 end exponent close parentheses to the power of n minus 2 end exponent x open parentheses a to the power of n over a to the power of negative 2 end exponent close parentheses to the power of n minus 2 end exponent x open parentheses fraction numerator a minus 2 over denominator a to the power of n end fraction close parentheses to the power of n minus 2 end exponent$

Pembahasan

Karena dan Maka Jadi nilai dari

$10 m equals 8 comma 3333 horizontal ellipsis bottom enclose space space space space space m equals 0 comma 8333 horizontal ellipsis space minus end enclose space minus 9 m equals negative 7 comma 5 m equals fraction numerator negative 7 comma 5 over denominator negative 9 end fraction equals 75 over 90 equals 5 over 6 10 n equals 6 comma 666 horizontal ellipsis bottom enclose space space space space space n equals 0 comma 6666 horizontal ellipsis space minus end enclose minus 9 n equals negative 6 n equals fraction numerator negative 6 over denominator negative 9 end fraction equals 2 over 3 open parentheses a to the power of m over a to the power of n close parentheses to the power of m plus n end exponent x open parentheses a to the power of n over a to the power of negative 2 end exponent close parentheses to the power of n minus 2 end exponent x open parentheses a to the power of negative 2 end exponent over a to the power of n close parentheses to the power of n minus 2 end exponent equals left parenthesis a to the power of m minus n end exponent right parenthesis to the power of m plus n end exponent cross times left parenthesis a to the power of n plus 2 end exponent right parenthesis to the power of n minus 2 end exponent cross times left parenthesis a to the power of negative 2 minus n end exponent right parenthesis to the power of n minus 2 end exponent equals a to the power of m squared minus m n plus n m minus n squared end exponent x space a to the power of n squared minus 2 n plus 2 n minus 4 end exponent x space a to the power of negative 2 n plus 4 minus n squared plus 2 n end exponent equals a to the power of m squared minus n squared end exponent x space a to the power of n squared minus 4 end exponent space x space a to the power of 4 minus n squared end exponent equals a to the power of m squared minus n squared plus n squared minus 4 plus 4 minus n squared end exponent equals a to the power of m squared minus n squared end exponent$

Karena dan

Maka

Jadi nilai dari $open parentheses a to the power of n over a to the power of negative 2 end exponent close parentheses to the power of n minus 2 end exponent x open parentheses a to the power of n over a to the power of negative 2 end exponent close parentheses to the power of n minus 2 end exponent x open parentheses fraction numerator a minus 2 over denominator a to the power of n end fraction close parentheses to the power of n minus 2 end exponent$