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Jika , konsentrasi ion oksalat yang diperlukan unt...

Jika begin mathsize 14px style K subscript sp space Ca C subscript 2 O subscript 4 equals 2 comma 6 cross times 10 to the power of negative sign 9 end exponent end style, konsentrasi ion oksalat yang diperlukan untuk membentuk endapan dalam larutan yang mengandung 0,02 M ion kalsium adalah undefined 

  1. begin mathsize 14px style 1 comma 0 cross times 10 to the power of negative sign 9 end exponent end style 

  2. begin mathsize 14px style 2 comma 2 cross times 10 to the power of negative sign 5 end exponent end style 

  3. begin mathsize 14px style 5 comma 2 cross times 10 to the power of negative sign 11 end exponent end style 

  4. begin mathsize 14px style 1 comma 3 cross times 10 to the power of negative sign 7 end exponent end style 

  5. begin mathsize 14px style 5 comma 2 cross times 10 to the power of negative sign 19 end exponent end style 

Jawaban:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell Ca C subscript 2 O subscript 4 italic open parentheses italic s italic close parentheses italic space end cell rightwards arrow over leftwards arrow cell space Ca to the power of 2 plus sign italic left parenthesis italic a italic q italic right parenthesis plus C subscript 2 O subscript 4 to the power of 2 minus sign end exponent italic left parenthesis italic a italic q italic right parenthesis end cell row blank blank cell space space space space space space space space s space space space space space space space space space space space space space space space space space space space s space space space space space space space space space space space space space space space space s end cell row cell K subscript sp end cell equals cell open square brackets Ca to the power of 2 plus sign close square brackets space space left square bracket C subscript 2 O subscript 4 to the power of 2 minus sign end exponent right square bracket end cell row cell 2 comma 6 cross times 10 to the power of negative sign 9 end exponent end cell equals cell 2 cross times 10 to the power of negative sign 2 end exponent middle dot left square bracket C subscript 2 O subscript 4 to the power of 2 minus sign end exponent right square bracket end cell row cell left square bracket C subscript 2 O subscript 4 to the power of 2 minus sign end exponent right square bracket end cell equals cell fraction numerator 2 comma 6 cross times 10 to the power of negative sign 9 end exponent over denominator 2 cross times 10 to the power of negative sign 2 end exponent end fraction end cell row cell left square bracket C subscript 2 O subscript 4 to the power of 2 minus sign end exponent right square bracket end cell equals cell 1 comma 3 cross times 10 to the power of negative sign 7 end exponent end cell end table end style 

Jadi, jawaban yang benar adalah (D).

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