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Jika hasil kali kelarutan BaCrO 4 ​ dalam air mumi adalah 2 x 1 0 − 10 , kelarutan dalam larutan Ba ( OH ) 2 ​ dengan pH = 12 + log 2 adalah ...

Jika hasil  kali kelarutan dalam air mumi adalah  , kelarutan undefined dalam larutan  dengan pH = 12 + log 2 adalah ...

  1. begin mathsize 14px style 1 comma 0 space x space 10 to the power of negative sign 9 space end exponent mol end style 

  2. begin mathsize 14px style 2 comma 0 space x space 10 to the power of negative sign 9 space end exponent mol end style 

  3. begin mathsize 14px style 5 comma 0 space x space 10 to the power of negative sign 9 end exponent space mol end style 

  4. begin mathsize 14px style 2 comma 0 space x space 10 to the power of negative sign 8 end exponent space mol end style 

  5. begin mathsize 14px style 2 comma 5 space x space 10 to the power of negative sign 8 end exponent space mol end style 

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begin mathsize 14px style Ba Cr O subscript 4 left parenthesis italic a italic q right parenthesis yields Ba to the power of 2 plus sign left parenthesis italic a italic q right parenthesis space plus space Cr O subscript 4 to the power of 2 minus sign end exponent left parenthesis italic a italic q right parenthesis space space space space space space space space s space space space space space space space space space space space space space space space space space space s space space space space space space space space space space space space space space space space space s  pH space space space space space space space equals space 12 space plus space log space 2 pOH space space space space equals space 2 space minus sign space log space 2 open square brackets O H to the power of minus sign close square brackets space equals space 2 space x space 10 to the power of negative sign 2 end exponent  Ba open parentheses O H close parentheses subscript 2 left parenthesis italic a italic q right parenthesis rightwards arrow space Ba to the power of 2 plus sign left parenthesis italic a italic q right parenthesis space plus space space 2 O H to the power of minus sign left parenthesis italic a italic q right parenthesis space space space space 0 comma 01 space space space space space space space space space space space space space 0 comma 01 space space space space space space space space space space space space space 0 comma 02 space  Ion space Ba to the power of 2 plus sign space space dimasukkan space ke space rumus space hasil space kali space ion bond ion space Ba Cr O subscript 4 space Ba Cr O subscript 4 left parenthesis italic a italic q right parenthesis yields Ba to the power of 2 plus sign left parenthesis italic a italic q right parenthesis space plus space Cr O subscript 4 to the power of 2 minus sign end exponent left parenthesis italic a italic q right parenthesis space comma space dalam space keadaan space tepat space jenuh Ksp double bond Qsp 2 space x space 10 to the power of negative sign 10 end exponent space equals space left square bracket Ba to the power of 2 plus sign right square bracket left square bracket Cr O subscript 4 to the power of 2 minus sign end exponent right square bracket space 2 space x space 10 to the power of negative sign 10 end exponent space equals space 1 space x 10 to the power of negative sign 2 end exponent open parentheses s close parentheses fraction numerator 2 space x space 10 to the power of negative sign 10 end exponent over denominator 1 space x 10 to the power of negative sign 2 end exponent end fraction space equals space s  s space equals space 2 space x space 10 to the power of negative sign 8 end exponent Jadi comma space kelarutan space Ba Cr O subscript 4 space dalam space larutan space Ba open parentheses O H close parentheses subscript 2 space tersebut space adalah space 2 space x space 10 to the power of negative sign 8 end exponent bold Jawaban bold space bold yang bold space bold benar bold space bold adalah bold space italic e end style  

 

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Bila diketahui K sp ​ AgI = 1 , 8 × 1 0 − 14 . Hitunglah kelarutan AgI dalam larutan HI 0,1 M.

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