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Jika diketahui begin mathsize 14px style K subscript sp space Ag subscript 2 Cr O subscript 4 end style pada begin mathsize 14px style t degree C end style adalah begin mathsize 14px style 1 comma 1 cross times 10 to the power of negative sign 12 end exponent end style. Hitunglah massa begin mathsize 14px style Ag subscript 2 Cr O subscript 4 end style yang dapat larut dalam 500 mL! (begin mathsize 14px style A subscript r end style Ag = 108, Cr = 52, O = 16)undefined

A. Kusbardini

Master Teacher

Mahasiswa/Alumni UIN Syarif Hidayatullah Jakarta

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah seperti penjelasan di atas.space

Pembahasan

Untuk dapat mengetahui jumlah begin mathsize 14px style Ag subscript 2 Cr O subscript 4 end style yang dapat larut dalam 500 mL larutan, maka perlu dihitung terlebih dahulu nilai kelarutan begin mathsize 14px style Ag subscript 2 Cr O subscript 4 end style dari nilai begin mathsize 14px style K subscript sp end stylenya. Menghitung kelarutan dapat dilakukan seperti berikut.space


begin mathsize 14px style Ag subscript 2 Cr O subscript 4 yields 2 Ag to the power of plus sign and Cr O subscript 4 to the power of 2 minus sign space space space space space space space space space space space space space space space space space space left parenthesis 2 s right parenthesis space space space space space space space space open parentheses s close parentheses end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp end cell equals cell open square brackets Ag to the power of plus sign close square brackets squared open square brackets Cr O subscript 4 to the power of 2 minus sign close square brackets end cell row cell K subscript sp end cell equals cell open parentheses 2 s close parentheses squared space open parentheses s close parentheses end cell row cell K subscript sp end cell equals cell 4 s cubed end cell row cell 1 comma 1 cross times 10 to the power of negative sign 12 end exponent end cell equals cell 4 s cubed end cell row cell s cubed end cell equals cell fraction numerator 1 comma 1 cross times 10 to the power of negative sign 12 end exponent over denominator 4 end fraction end cell row cell s cubed end cell equals cell 0 comma 275 cross times 10 to the power of negative sign 12 end exponent end cell row cell s cubed end cell equals cell 275 cross times 10 to the power of negative sign 15 end exponent end cell row s equals cell cube root of 275 cross times 10 to the power of negative sign 15 end exponent end root end cell row s equals cell 6 comma 5 cross times 10 to the power of negative sign 5 end exponent end cell end table end style   


Berdasarkan perhitungan di atas, diketahui kelarutan begin mathsize 14px style Ag subscript 2 Cr O subscript 4 end style adalah begin mathsize 14px style 6 comma 5 cross times 10 to the power of negative sign 5 end exponent space bevelled mol over L end style, maka massa begin mathsize 14px style Ag subscript 2 Cr O subscript 4 end style yang terlarut dalam 500 mL larutannya adalah sebagai berikut.space


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row s equals cell m over M subscript r cross times fraction numerator 1000 over denominator volume space open parentheses mL close parentheses end fraction end cell row cell 6 comma 5 cross times 10 to the power of negative sign 5 end exponent end cell equals cell m over 332 cross times 1000 over 500 end cell row cell 0 comma 02158 end cell equals cell m cross times 2 end cell row m equals cell fraction numerator 0 comma 02158 over denominator 2 end fraction end cell row m equals cell 0 comma 01079 space gram end cell end table end style 


Jadi, jawaban yang tepat adalah seperti penjelasan di atas.space

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