Pertanyaan

Jika di dalam laboratorium terdapat 500 mL larutan NaOH 1%, volume air dalam larutan tersebut adalah ....

5 mL
495 mL
499 mL
500 mL
505 mL

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J. Siregar

Master Teacher

Mahasiswa/Alumni Universitas Negeri Medan

Jawaban terverifikasi

Pembahasan

volume larutan = volume zat terlarut + volume zat pelarut volume larutan = volume NaOH + volume air 500 mL = 5 mL + volume air volume air = 495 mL

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell percent sign volume end cell equals cell fraction numerator volume blank zat blank terlarut over denominator volume blank larutan end fraction straight x 100 straight percent sign end cell row cell 1 straight percent sign end cell equals cell fraction numerator volume blank zat blank terlarut over denominator 500 blank mL end fraction straight x 100 straight percent sign end cell row cell volume blank zat blank terlarut end cell equals cell 5 mL end cell end table end style$

volume larutan = volume zat terlarut + volume zat pelarut

volume larutan = volume NaOH + volume air

500 mL = 5 mL + volume air

volume air = 495 mL