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Ion X2− dan 1840​Ar merupakan isoelektronik. Konfigurasi elektron unsur X adalah

Pertanyaan

Ion X to the power of 2 minus end exponent space d a n space A presubscript 18 presuperscript 40 r merupakan isoelektronik. Konfigurasi elektron unsur X adalah

  1. 1 s squared space 2 s squared space 2 p to the power of 6 space 3 s squared space 3 p to the power of 6 space end exponent 4 s squared space 3 d to the power of 10 space 4 p to the power of 6 space 5 s squared space 4 d to the power of 4

  2. 1 s squared space 2 s squared space 2 p to the power of 6 space 3 s squared space 3 p to the power of 6 space end exponent 4 s squared space 3 d to the power of 10 space 4 p to the power of 6 space 5 s squared space 4 d squared

  3. 1 s squared space 2 s squared space 2 p to the power of 6 space 3 s squared space 3 p to the power of 6 space end exponent 4 s squared space 3 d to the power of 10 space 4 p to the power of 6 space 5 s squared

  4. 1 s squared space 2 s squared space 2 p to the power of 6 space 3 s squared space 3 p to the power of 6 space end exponent

  5. 1 s squared space 2 s squared space 2 p to the power of 6 space 3 s squared space 3 p to the power of 4 space end exponent

A. Tiara

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Jawaban

konfigurasi dari X presubscript 16 space a d a l a h space 1 s squared space 2 s squared space 2 p to the power of 6 space 3 s squared space 3 p to the power of 4

Pembahasan

Isoelektronik artinya memiliki jumlah elektron yang sama A presubscript 18 r memiliki18 elektron jadi X to the power of negative 2 end exponent juga memiliki 18 elektron. Tanda -2 artinya telah menangkap 2 elektron, sehingga atom X sendiri memiliki 16 elektron

Sehingga konfigurasi dari X presubscript 16 space a d a l a h space 1 s squared space 2 s squared space 2 p to the power of 6 space 3 s squared space 3 p to the power of 4

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Ion X2− dan 1840​Ar merupakan isoelektronik. Konfigurasi elektron unsur X adalah ....  (SBMPTN 2017)

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