Ion merupakan isoelektronik. Konfigurasi elektron ...

Ion $X to the power of 2 minus end exponent space d a n space A presubscript 18 presuperscript 40 r$ merupakan isoelektronik. Konfigurasi elektron unsur X adalah

$1 s squared space 2 s squared space 2 p to the power of 6 space 3 s squared space 3 p to the power of 6 space end exponent 4 s squared space 3 d to the power of 10 space 4 p to the power of 6 space 5 s squared space 4 d to the power of 4$
$1 s squared space 2 s squared space 2 p to the power of 6 space 3 s squared space 3 p to the power of 6 space end exponent 4 s squared space 3 d to the power of 10 space 4 p to the power of 6 space 5 s squared space 4 d squared$
$1 s squared space 2 s squared space 2 p to the power of 6 space 3 s squared space 3 p to the power of 6 space end exponent 4 s squared space 3 d to the power of 10 space 4 p to the power of 6 space 5 s squared$
$1 s squared space 2 s squared space 2 p to the power of 6 space 3 s squared space 3 p to the power of 6 space end exponent$
$1 s squared space 2 s squared space 2 p to the power of 6 space 3 s squared space 3 p to the power of 4 space end exponent$

Jawaban:

Isoelektronik artinya memiliki jumlah elektron yang sama $A presubscript 18 r$ memiliki18 elektron jadi $X to the power of negative 2 end exponent$ juga memiliki 18 elektron. Tanda -2 artinya telah menangkap 2 elektron, sehingga atom X sendiri memiliki 16 elektron

Sehingga konfigurasi dari $X presubscript 16 space a d a l a h space 1 s squared space 2 s squared space 2 p to the power of 6 space 3 s squared space 3 p to the power of 4$

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