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Hitunglah massa dari: a. 0,5 mol barium (  Ba = 137) b. 5 mol belerang ( S = 32) c. 2,5 mol  ( K = 19, S = 32, dan O = 16) d. 0,3 mol  ( C = 12 dan O = 16) e. 10 mol  ( K = 39, Cr = 52, dan O = 16)

Pertanyaan

Hitunglah massa dari:
a. 0,5 mol barium (A subscript r  Ba = 137)
b. 5 mol belerang (A subscript r S = 32)
c. 2,5 mol K subscript 2 S O subscript 4 (A subscript r K = 19, S = 32, dan O = 16)
d. 0,3 mol C O subscript 2 (A subscript r C = 12 dan O = 16)
e. 10 mol K subscript 2 Cr subscript 2 O subscript 7 (A subscript r K = 39, Cr = 52, dan O = 16)

Pembahasan Soal:

Massa suatu zat dihitung menggunakan rumus hubungan antara massa dengan mol, yaitu seperti berikut:

massa double bond n cross times Mr

a. 
massa space Ba double bond n cross times Mr space space space space space space space space space space space space space space space equals 0 comma 5 cross times 137 space space space space space space space space space space space space space space space equals 68 comma 5 space gram 

b.
massa space S double bond n cross times Mr space space space space space space space space space space space space space equals 5 cross times 32 space space space space space space space space space space space space space equals 160 space gram 

c.
massa space K subscript 2 S O subscript 4 double bond n cross times Mr space space space space space space space space space space space space space space space space space space space space space equals 2 comma 5 cross times left parenthesis 2 cross times 19 plus 32 plus 4 cross times 16 right parenthesis space space space space space space space space space space space space space space space space space space space space space equals 2 comma 5 cross times 134 space space space space space space space space space space space space space space space space space space space space space equals 335 space gram 

d.
massa space C O subscript 2 double bond n cross times Mr space space space space space space space space space space space space space space space space space space equals 0 comma 3 cross times left parenthesis 12 plus 2 cross times 16 right parenthesis space space space space space space space space space space space space space space space space space space equals 0 comma 3 cross times 44 space space space space space space space space space space space space space space space space space space equals 13 comma 2 space gram  

e. 
massa space K subscript 2 Cr subscript 2 O subscript 7 double bond n cross times Mr space space space space space space space space space space space space space space space space space space space space space space space space equals 10 cross times left parenthesis 2 cross times 19 plus 2 cross times 52 plus 7 cross times 16 right parenthesis space space space space space space space space space space space space space space space space space space space space space space space space equals 2540 space gram 

Jadi, massa dari masing - masing zat yaitu barium = 68,5 g, belerang = 160 g, K subscript 2 S O subscript 4 = 335 g, C O subscript 2 = 13,2 g, dan K subscript 2 Cr subscript 2 O subscript 7 = 2540 g.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 03 Juni 2021

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