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Hitunglah konsentrasi ion H + dan OH − dalam larutan Ba ( OH ) 2 ​ 0,005 Mserta harga pH-nya pada suhu 30 ∘ C ! ( K w ​ = 1 , 47 × 1 0 − 14 )

Hitunglah konsentrasi ion  dan  dalam larutan  0,005 M serta harga pH-nya pada suhu !  

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Diketahui: Ditanya: pH larutan = ? Jawab: termasuk jenis basa kuat dimana nilai derajat disosiasinya diasumsikan = 1. Maka, perhitungannya menjadi sebagai berikut: Sehingga, pH larutan dapat dihitung: Oleh karena itu, konsentrasi dan secara berturut-turut adalah serta pH larutan = 11,53.

Diketahui:

Error converting from MathML to accessible text.  

begin mathsize 14px style K subscript w space equals space 1 comma 47 cross times 10 to the power of negative sign 14 end exponent end style 

Ditanya: 

begin mathsize 14px style open square brackets H to the power of plus sign close square brackets space dan space open square brackets O H to the power of minus sign close square brackets space equals space ? end style 

pH larutan = ?

Jawab:

begin mathsize 14px style Ba open parentheses O H close parentheses subscript 2 end style termasuk jenis basa kuat dimana nilai derajat disosiasinya diasumsikan = 1. Maka, perhitungannya menjadi sebagai berikut:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell alpha cross times Mb end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 1 cross times 0 comma 005 space M end cell row cell bold open square brackets O H to the power of bold minus sign bold close square brackets end cell bold equals cell bold 5 bold cross times bold 10 to the power of bold minus sign bold 3 end exponent bold space italic M end cell row blank blank blank row cell K subscript w end cell equals cell open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell fraction numerator K subscript w over denominator open square brackets O H to the power of minus sign close square brackets end fraction end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell fraction numerator 1 comma 47 cross times 10 to the power of negative sign 14 end exponent over denominator 5 cross times 10 to the power of negative sign 3 end exponent space M end fraction end cell row cell bold open square brackets H to the power of bold plus sign bold close square brackets end cell bold equals cell bold 2 bold comma bold 94 bold cross times bold 10 to the power of bold minus sign bold 12 end exponent bold space italic M end cell row blank blank blank end table end style   

Sehingga, pH larutan dapat dihitung:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell negative sign log open square brackets H to the power of plus sign close square brackets end cell row pH equals cell negative sign log open parentheses 2 comma 94 cross times 10 to the power of negative sign 12 end exponent close parentheses end cell row pH equals cell 12 minus sign log open parentheses 2 comma 94 close parentheses end cell row bold pH bold equals cell bold 11 bold comma bold 53 end cell end table end style 

Oleh karena itu, konsentrasi begin mathsize 14px style H to the power of plus sign end style dan begin mathsize 14px style O H to the power of minus sign end style secara berturut-turut adalah begin mathsize 14px style 5 cross times 10 to the power of negative sign 3 end exponent space M space dan space 2 comma 94 cross times 10 to the power of negative sign 12 end exponent space M end style serta pH larutan = 11,53. 

 

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