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Pertanyaan

Hitunglah kelarutan Ag 2 ​ SO 4 ​ ( K sp ​ = 1 , 5 × 1 0 − 5 ) dalam: b. 0,2 M Na 2 ​ SO 4 ​

Hitunglah kelarutan  dalam:

b.  0,2 M  

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S. Lubis

Master Teacher

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kelarutan dalam 0,2 M sebesar .

kelarutan bottom enclose Ag subscript bold 2 S O subscript 4 end enclose dalam bottom enclose Na subscript bold 2 S O subscript bold 4 end enclose 0,2 M sebesar bottom enclose bold 4 bold comma bold 33 bold cross times bold 10 to the power of bold minus sign bold 3 end exponent end enclose.

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Pembahasan

Jadi, kelarutan dalam 0,2 M sebesar .

stack Ag subscript 2 S O subscript 4 with s below rightwards harpoon over leftwards harpoon stack 2 Ag to the power of plus sign with 2 s below plus stack S O subscript 4 to the power of 2 minus sign end exponent with s below stack Na subscript 2 S O subscript 4 with 0 comma 2 space M below yields 2 Na to the power of plus sign plus stack S O subscript 4 to the power of 2 minus sign end exponent with 0 comma 2 space M below 

table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp space Ag subscript 2 S O subscript 4 end cell equals cell open square brackets Ag to the power of plus sign close square brackets squared left square bracket S O subscript 4 to the power of 2 minus sign end exponent right square bracket end cell row cell 1 comma 5 cross times 10 to the power of negative sign 5 end exponent end cell equals cell left parenthesis 2 s right parenthesis squared left parenthesis s plus 0 comma 2 right parenthesis end cell row cell 1 comma 5 cross times 10 to the power of negative sign 5 end exponent end cell equals cell left parenthesis 4 s squared right parenthesis left parenthesis 0 comma 2 right parenthesis end cell row cell 1 comma 5 cross times 10 to the power of negative sign 5 end exponent end cell equals cell 0 comma 8 s squared end cell row cell s squared end cell equals cell fraction numerator 1 comma 5 cross times 10 to the power of negative sign 5 end exponent over denominator 0 comma 8 end fraction end cell row s equals cell square root of 1 comma 875 cross times 10 to the power of negative sign 5 end exponent end root end cell row s equals cell 4 comma 33 cross times 10 to the power of negative sign 3 end exponent end cell end table 


Jadi, kelarutan bottom enclose Ag subscript bold 2 S O subscript 4 end enclose dalam bottom enclose Na subscript bold 2 S O subscript bold 4 end enclose 0,2 M sebesar bottom enclose bold 4 bold comma bold 33 bold cross times bold 10 to the power of bold minus sign bold 3 end exponent end enclose.

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