Iklan

Iklan

Pertanyaan

Hitunglah kelarutan Ag 2 ​ SO 4 ​ ( K sp ​ = 1 , 5 × 1 0 − 5 ) dalam: b. 0,2 M Na 2 ​ SO 4 ​

Hitunglah kelarutan  dalam:

b.  0,2 M  

Iklan

S. Lubis

Master Teacher

Jawaban terverifikasi

Jawaban

kelarutan dalam 0,2 M sebesar .

kelarutan bottom enclose Ag subscript bold 2 S O subscript 4 end enclose dalam bottom enclose Na subscript bold 2 S O subscript bold 4 end enclose 0,2 M sebesar bottom enclose bold 4 bold comma bold 33 bold cross times bold 10 to the power of bold minus sign bold 3 end exponent end enclose.

Iklan

Pembahasan

Jadi, kelarutan dalam 0,2 M sebesar .

stack Ag subscript 2 S O subscript 4 with s below rightwards harpoon over leftwards harpoon stack 2 Ag to the power of plus sign with 2 s below plus stack S O subscript 4 to the power of 2 minus sign end exponent with s below stack Na subscript 2 S O subscript 4 with 0 comma 2 space M below yields 2 Na to the power of plus sign plus stack S O subscript 4 to the power of 2 minus sign end exponent with 0 comma 2 space M below 

table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp space Ag subscript 2 S O subscript 4 end cell equals cell open square brackets Ag to the power of plus sign close square brackets squared left square bracket S O subscript 4 to the power of 2 minus sign end exponent right square bracket end cell row cell 1 comma 5 cross times 10 to the power of negative sign 5 end exponent end cell equals cell left parenthesis 2 s right parenthesis squared left parenthesis s plus 0 comma 2 right parenthesis end cell row cell 1 comma 5 cross times 10 to the power of negative sign 5 end exponent end cell equals cell left parenthesis 4 s squared right parenthesis left parenthesis 0 comma 2 right parenthesis end cell row cell 1 comma 5 cross times 10 to the power of negative sign 5 end exponent end cell equals cell 0 comma 8 s squared end cell row cell s squared end cell equals cell fraction numerator 1 comma 5 cross times 10 to the power of negative sign 5 end exponent over denominator 0 comma 8 end fraction end cell row s equals cell square root of 1 comma 875 cross times 10 to the power of negative sign 5 end exponent end root end cell row s equals cell 4 comma 33 cross times 10 to the power of negative sign 3 end exponent end cell end table 


Jadi, kelarutan bottom enclose Ag subscript bold 2 S O subscript 4 end enclose dalam bottom enclose Na subscript bold 2 S O subscript bold 4 end enclose 0,2 M sebesar bottom enclose bold 4 bold comma bold 33 bold cross times bold 10 to the power of bold minus sign bold 3 end exponent end enclose.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

5

Iklan

Iklan

Pertanyaan serupa

Bila diketahui K sp ​ AgI = 1 , 8 × 1 0 − 14 . Hitunglah kelarutan AgI dalam larutan HI 0,1 M.

12

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia