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Hitunglah banyaknya mol dari: a. 8 gram  (Ar H = 1) b. 800 gram  (Ar Ca = 40, C = 12, dan O = 16) c. 232 gram  (Ar Mg = 24, O = 16, dan H = 1) d. 158 gram  (Ar K = 39, Mn = 55, dan O = 16)

Pertanyaan

Hitunglah banyaknya mol dari:
a. 8 gram H subscript 2 (Ar H = 1)
b. 800 gram Ca C O subscript 3 (Ar Ca = 40, C = 12, dan O = 16)
c. 232 gram Mg open parentheses O H close parentheses subscript 2 (Ar Mg = 24, O = 16, dan H = 1)
d. 158 gram K Mn O subscript 4 (Ar K = 39, Mn = 55, dan O = 16)

Pembahasan Soal:

Banyaknya mol suatu zat dapat dihitung menggunakan rumus hubungan antara mol dengan massa zat, yaitu seperti berikut:

n equals massa over Mr 

a.
n space H subscript 2 equals massa over Mr space space space space space space space equals 8 over 2 space space space space space space space equals 4 space mol

b.
n space Ca C O subscript 3 equals massa over Mr space space space space space space space space space space space space space space equals fraction numerator 800 over denominator left parenthesis 40 plus 12 plus 3 cross times 16 right parenthesis end fraction space space space space space space space space space space space space space space equals 800 over 100 space space space space space space space space space space space space space space equals 8 space mol 

c.
n space Mg open parentheses O H close parentheses subscript 2 equals fraction numerator massa over denominator Mr end fraction space space space space space space space space space space space space space space space space space equals fraction numerator 232 over denominator left parenthesis 24 plus 2 cross times 16 plus 2 cross times 1 right parenthesis end fraction space space space space space space space space space space space space space space space space space equals 232 over 58 space space space space space space space space space space space space space space space space space equals 4 space mol 

d.
 n space K Mn O subscript 4 equals massa over Mr space space space space space space space space space space space space space space equals fraction numerator 158 over denominator left parenthesis 39 plus 55 plus 4 cross times 16 right parenthesis end fraction space space space space space space space space space space space space space space equals 158 over 158 space space space space space space space space space space space space space space equals 1 space mol 

Jadi, jumlah mol masing masing zat yaitu H subscript 2 = 4 mol, Ca C O subscript 3 = 8 mol, Mg open parentheses O H close parentheses subscript 2 = 4 mol, dan K Mn O subscript 4 = 1 mol.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 03 Juni 2021

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