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Hasil pengakaran dari ( 6 25 ​ ) 7 2 ​ ( 3 5 ​ ) 7 2 ​ ​ adalah ...

Hasil pengakaran dari  adalah ...

  1. 2

  2. 1 half

  3. 1

  4. 0

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F. Pratama

Master Teacher

Mahasiswa/Alumni Universitas Putra Indonesia YPTK Padang

Jawaban terverifikasi

Pembahasan

fraction numerator left parenthesis cube root of 5 right parenthesis to the power of begin display style 2 over 7 end style end exponent over denominator left parenthesis root index 6 of 25 right parenthesis to the power of begin display style 2 over 7 end style end exponent end fraction equals fraction numerator left parenthesis 5 to the power of begin display style 1 third end style end exponent right parenthesis to the power of begin display style 2 over 7 end style end exponent over denominator left parenthesis left parenthesis 5 squared right parenthesis to the power of begin display style 1 over 6 end style end exponent right parenthesis to the power of begin display style 2 over 7 end style end exponent end fraction equals 5 to the power of begin display style 1 third end style cross times begin display style 2 over 7 end style end exponent over 5 to the power of 2 cross times begin display style 1 over 6 end style cross times begin display style 2 over 7 end style end exponent equals 5 to the power of begin display style 2 over 21 end style end exponent over 5 to the power of begin display style 2 over 21 end style end exponent equals 1

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Hasil dari 28 10 ​ ÷ 4 5 ​ adalah ....

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