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Hasil integral ∫ ( 2 x − 1 ) ( 4 − 3 x ) d x = ...

Hasil integral $\int (2 x - 1) (4 - 3 x) d x = ...$

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$table attributes columnalign right center left columnspacing 0px end attributes row cell integral left parenthesis 2 x minus 1 right parenthesis left parenthesis 4 minus 6 x right parenthesis d x end cell equals cell integral left parenthesis 8 x minus 12 x squared minus 4 plus 6 x right parenthesis d x end cell row blank equals cell integral left parenthesis negative 12 x squared plus 14 x minus 4 right parenthesis d x end cell row blank equals cell negative fraction numerator 12 over denominator 2 plus 1 end fraction x to the power of 2 plus 1 end exponent plus fraction numerator 14 over denominator 1 plus 1 end fraction x to the power of 1 plus 1 end exponent minus fraction numerator 4 over denominator 0 plus 1 end fraction x to the power of 0 plus 1 end exponent plus C end cell row blank equals cell negative 12 over 3 x cubed plus 14 over 2 x squared minus 4 over 1 x to the power of 1 plus C end cell row blank equals cell negative 4 x cubed plus 7 x squared minus 4 x plus C end cell end table$