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Pertanyaan

Hasil dari ∫ ( x 2 − x − 1 ) 2 ( 12 x − 6 ) ​ d x = ....

Hasil dari

  1. negative fraction numerator 6 over denominator x squared minus x minus 1 end fraction plus space C

  2. negative fraction numerator 3 over denominator x squared minus x minus 1 end fraction plus space C

  3. negative fraction numerator 2 over denominator x squared minus x minus 1 end fraction plus space C

  4. 2 over open parentheses x squared minus x minus 1 close parentheses cubed plus space C

  5. 3 over open parentheses x squared minus x minus 1 close parentheses cubed

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I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Pembahasan

Misal : Maka integral taktentunya adalah

integral fraction numerator 12 x minus 6 over denominator open parentheses x squared minus x minus 1 close parentheses squared end fraction d x equals integral 6 open parentheses 2 x minus 1 close parentheses open parentheses x squared minus x minus 1 close parentheses to the power of negative 1 end exponent d x

Misal : text U end text equals x squared minus x minus 1

         text dU end text equals 2 x minus 1 d x text dx end text equals fraction numerator d U over denominator 2 x minus 1 end fraction

integral fraction numerator 12 x minus 6 over denominator open parentheses x squared minus x minus 1 close parentheses squared end fraction d x equals integral 6 open parentheses 2 x minus 1 close parentheses U to the power of negative 2 end exponent fraction numerator d U over denominator 2 x minus 1 end fraction equals integral 6 U to the power of negative 2 end exponent d U equals fraction numerator 6 over denominator negative 1 end fraction U to the power of negative 1 end exponent plus C equals fraction numerator negative 6 over denominator U end fraction plus C

Maka integral taktentunya adalah

fraction numerator negative 6 over denominator U end fraction plus C equals fraction numerator negative 6 over denominator open parentheses x squared minus x minus 1 close parentheses end fraction plus C

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