Roboguru
SD
SMP
SMA
UTBK/SNBT

Iklan

Pertanyaan

Hasil dari adalah ....

Hasil dari begin mathsize 14px style open parentheses x to the power of a over x to the power of b close parentheses to the power of a plus b end exponent times open parentheses x to the power of b over x to the power of c close parentheses to the power of b plus c end exponent times open parentheses x to the power of c over x to the power of a close parentheses to the power of c plus a end exponent end style adalah ....

  1. begin mathsize 14px style open parentheses x to the power of a over x to the power of b close parentheses to the power of c end style  

  2. begin mathsize 14px style open parentheses x to the power of b over x to the power of c close parentheses to the power of a end style  

  3. 0

  4. begin mathsize 14px style 1 end style

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

02

:

00

:

49

:

40

Klaim

Iklan

N. Putri

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepatadalah E.

jawaban yang tepat adalah E.

Pembahasan

Perhatikan bahwa Jadi, jawaban yang tepatadalah E.

Perhatikan bahwa

begin mathsize 14px style open parentheses x to the power of a over x to the power of b close parentheses to the power of a plus b end exponent times open parentheses x to the power of b over x to the power of c close parentheses to the power of b plus c end exponent times open parentheses x to the power of c over x to the power of a close parentheses to the power of c plus a end exponent equals open parentheses x to the power of a open parentheses a plus b close parentheses end exponent over x to the power of b open parentheses a plus b close parentheses end exponent close parentheses times open parentheses x to the power of b open parentheses b plus c close parentheses end exponent over x to the power of c open parentheses b plus c close parentheses end exponent close parentheses times open parentheses x to the power of c open parentheses c plus a close parentheses end exponent over x to the power of a open parentheses c plus a close parentheses end exponent close parentheses equals open parentheses x to the power of a squared plus a b end exponent over x to the power of a b plus b squared end exponent close parentheses times open parentheses x to the power of b squared plus b c end exponent over x to the power of b c plus c squared end exponent close parentheses times open parentheses x to the power of c squared plus a c end exponent over x to the power of a c plus a squared end exponent close parentheses equals x to the power of open parentheses a squared plus a b close parentheses minus open parentheses a b plus b squared close parentheses end exponent times x to the power of open parentheses b squared plus b c close parentheses minus open parentheses b c plus c squared close parentheses end exponent times x to the power of open parentheses c squared plus a c close parentheses minus open parentheses a c plus a squared close parentheses end exponent equals x to the power of a squared minus b squared end exponent times x to the power of b squared minus c squared end exponent times x to the power of c squared minus a squared end exponent equals x to the power of a squared minus b squared plus b squared minus c squared plus c squared minus a squared end exponent equals x to the power of 0 equals box enclose 1 end style

Jadi, jawaban yang tepat adalah E.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Gold Icon

Klaim Gold gratis sekarang!

Dengan Gold kamu bisa tanya soal ke Forum sepuasnya, lho.

Pertanyaan serupa

Bentuk sederhana dari 27 x 4 y − 3 3 x − 3 y − 2 z 4 ​ adalah ....

2

4.2

Jawaban terverifikasi

Perhatikan pernyataan berikut! Pernyataan di atas yang bernilai BENAR ditunjukkan oleh....

5

0.0

Jawaban terverifikasi

Iklan

Bentuk sederhana dari adalah ....

1

5.0

Jawaban terverifikasi

Nilai dari b 3 2 ​ + 3 b − 1 − 2 b 0 a 2 3 ​ + 4 a − 1 − 5 a 0 ​ bila a = 4 dan b = 8 1 ​ adalah ....

2

5.0

Jawaban terverifikasi

Bentuk sederhana dari 27 x 4 y − 3 3 x − 3 y − 2 z 4 ​ adalah ....

2

4.2

Jawaban terverifikasi
Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Download di Google Play

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Produk Lainnya

Bantuan & Panduan

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia