Pertanyaan

Hasil dari adalah ....

$begin mathsize 14px style fraction numerator 2 over denominator 3 x to the power of 11 y to the power of 7 end fraction end style$
$begin mathsize 14px style fraction numerator 2 x to the power of 5 y to the power of 7 over denominator 3 end fraction end style$
$begin mathsize 14px style fraction numerator 2 y to the power of 11 over denominator 3 x to the power of 11 end fraction end style$
$begin mathsize 14px style fraction numerator 2 x to the power of 5 over denominator 3 y to the power of 7 end fraction end style$

A. Khairunisa

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah D.

Pembahasan

Perhatikan bahwa Jadi, hasil dari adalah . Dengan demikian, jawaban yang tepat adalah D.

Perhatikan bahwa

$begin mathsize 12px style square root of 18 cube root of 512 x to the power of negative 18 end exponent y to the power of 12 end root end root divided by 2 fourth root of cube root of square root of open parentheses 729 x to the power of negative 24 end exponent y to the power of 27 close parentheses to the power of 8 end root end root end root equals fraction numerator square root of 18 cube root of 512 x to the power of negative 18 end exponent y to the power of 12 end root end root over denominator 2 fourth root of cube root of square root of open parentheses 729 x to the power of negative 24 end exponent y to the power of 27 close parentheses to the power of 8 end root end root end root end fraction equals fraction numerator square root of 18 open parentheses 8 cubed x to the power of negative 18 end exponent y to the power of 12 close parentheses to the power of 1 third end exponent end root over denominator 2 fourth root of cube root of open parentheses open parentheses 729 x to the power of negative 24 end exponent y to the power of 27 close parentheses to the power of 8 close parentheses to the power of 1 half end exponent end root end root end fraction equals fraction numerator square root of 18 open parentheses 8 to the power of 3 cross times 1 third end exponent x to the power of negative 18 cross times 1 third end exponent y to the power of 12 cross times 1 third end exponent close parentheses end root over denominator 2 fourth root of cube root of open parentheses 729 x to the power of negative 24 end exponent y to the power of 27 close parentheses to the power of 4 end root end root end fraction equals fraction numerator square root of 18 open parentheses 8 x to the power of negative 6 end exponent y to the power of 4 close parentheses end root over denominator 2 fourth root of open parentheses open parentheses 729 x to the power of negative 24 end exponent y to the power of 27 close parentheses to the power of 4 close parentheses to the power of 1 third end exponent end root end fraction equals fraction numerator square root of 144 x to the power of negative 6 end exponent y to the power of 4 end root over denominator 2 fourth root of open parentheses 729 x to the power of negative 24 end exponent y to the power of 27 close parentheses to the power of 4 over 3 end exponent end root end fraction equals fraction numerator open parentheses 12 squared x to the power of negative 6 end exponent y to the power of 4 close parentheses to the power of 1 half end exponent over denominator 2 open parentheses open parentheses 729 x to the power of negative 24 end exponent y to the power of 27 close parentheses to the power of 4 over 3 end exponent close parentheses to the power of 1 fourth end exponent end fraction equals fraction numerator 12 x to the power of negative 3 end exponent y squared over denominator 2 open parentheses 729 x to the power of negative 24 end exponent y to the power of 27 close parentheses to the power of 1 third end exponent end fraction equals fraction numerator 6 x to the power of negative 3 end exponent y squared over denominator open parentheses 9 cubed x to the power of negative 24 end exponent y to the power of 27 close parentheses to the power of 1 third end exponent end fraction equals fraction numerator 6 x to the power of negative 3 end exponent y squared over denominator 9 x to the power of negative 8 end exponent y to the power of 9 end fraction equals 2 over 3 x to the power of negative 3 minus open parentheses negative 8 close parentheses end exponent y to the power of 2 minus 9 end exponent equals 2 over 3 x to the power of 5 y to the power of negative 7 end exponent equals fraction numerator 2 x to the power of 5 over denominator 3 y to the power of 7 end fraction end style$

Jadi, hasil dari adalah .

Dengan demikian, jawaban yang tepat adalah D.