Hasil dari 3422−623729a−54b24 adalah ....

Pertanyaan

Hasil dari $begin mathsize 14px style fraction numerator cube root of square root of 729 a to the power of negative 54 end exponent b to the power of 24 end root end root over denominator cube root of 42 squared minus 6 squared end root end fraction end style$ adalah ....

$begin mathsize 14px style fraction numerator b to the power of 4 over denominator 4 a to the power of 9 end fraction end style$
$begin mathsize 14px style fraction numerator b to the power of 8 over denominator 3 a to the power of 18 end fraction end style$
$begin mathsize 14px style fraction numerator a to the power of 18 b to the power of 4 over denominator 8 end fraction end style$
$begin mathsize 14px style fraction numerator a to the power of 9 b to the power of 4 over denominator 4 end fraction end style$

F. Ayudhita

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah A.

Pembahasan

Ingat bahwa

Maka

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator cube root of square root of 729 a to the power of negative 54 end exponent b to the power of 24 end root end root over denominator cube root of 42 squared minus 6 squared end root end fraction end cell equals cell fraction numerator cube root of open parentheses 3 to the power of 6 a to the power of negative 54 end exponent b to the power of 24 close parentheses to the power of 1 half end exponent end root over denominator cube root of open parentheses 42 plus 6 close parentheses open parentheses 42 minus 6 close parentheses end root end fraction end cell row blank equals cell fraction numerator open parentheses open parentheses 3 to the power of 6 a to the power of negative 54 end exponent b to the power of 24 close parentheses to the power of 1 half end exponent close parentheses to the power of 1 third end exponent over denominator cube root of 48 times 36 end root end fraction end cell row blank equals cell fraction numerator open parentheses 3 to the power of 6 a to the power of negative 54 end exponent b to the power of 24 close parentheses to the power of 1 over 6 end exponent over denominator cube root of open parentheses 2 to the power of 4 times 3 close parentheses times open parentheses 2 squared times 3 squared close parentheses end root end fraction end cell row blank equals cell fraction numerator 3 to the power of 6 cross times 1 over 6 end exponent a to the power of negative 54 cross times 1 over 6 end exponent b to the power of 24 cross times 1 over 6 end exponent over denominator cube root of 2 to the power of 6 times 3 cubed end root end fraction end cell row blank equals cell fraction numerator 3 a to the power of negative 9 end exponent b to the power of 4 over denominator open parentheses 2 to the power of 6 times 3 cubed close parentheses to the power of 1 third end exponent end fraction end cell row blank equals cell fraction numerator 3 a to the power of negative 9 end exponent b to the power of 4 over denominator 2 to the power of 6 cross times 1 third end exponent times 3 to the power of 3 cross times 1 third end exponent end fraction end cell row blank equals cell fraction numerator 3 a to the power of negative 9 end exponent b to the power of 4 over denominator 2 squared times 3 end fraction end cell row blank equals cell fraction numerator b to the power of 4 over denominator 4 a to the power of 9 end fraction end cell end table end style$

Jadi, hasil dari undefined adalah .

Dengan demikian, jawaban yang tepat adalah A.