Harga tetapan kesetimbangan (Kc) untuk reaksi: 4NH3​(g)+3O2​(g)⇌2N2​(g)+6H2​O(g) diperoleh dari persamaan ...

Pertanyaan

Harga tetapan kesetimbangan (Kc) untuk reaksi:


4 N H subscript 3 open parentheses italic g close parentheses and 3 O subscript 2 open parentheses italic g close parentheses equilibrium 2 N subscript 2 open parentheses italic g close parentheses and 6 H subscript 2 O open parentheses italic g close parentheses


diperoleh dari persamaan ...space

  1. K subscript c equals fraction numerator open square brackets N subscript 2 close square brackets open square brackets H subscript 2 O close square brackets over denominator open square brackets N H subscript 3 close square brackets open square brackets O subscript 2 close square brackets end fractionspace

  2. K subscript c equals fraction numerator open square brackets N H subscript 3 close square brackets open square brackets O subscript 2 close square brackets over denominator open square brackets N subscript 2 close square brackets open square brackets H subscript 2 O close square brackets end fractionspace

  3. K subscript c equals fraction numerator open square brackets N subscript 2 close square brackets squared open square brackets H subscript 2 O close square brackets to the power of 6 over denominator open square brackets N H subscript 3 close square brackets to the power of 4 open square brackets O subscript 2 close square brackets cubed end fractionspace

  4. K subscript c equals fraction numerator open square brackets N H subscript 3 close square brackets to the power of 4 open square brackets O subscript 2 close square brackets cubed over denominator open square brackets N subscript 2 close square brackets squared open square brackets H subscript 2 O close square brackets to the power of 6 end fractionspace

  5. K subscript c equals fraction numerator open square brackets N subscript 2 close square brackets to the power of 6 open square brackets H subscript 2 O close square brackets squared over denominator open square brackets N H subscript 3 close square brackets cubed open square brackets O subscript 2 close square brackets to the power of 4 end fractionspace

S. Lubis

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah C.space

Pembahasan

Tetapan kesetimbangan berdasarkan konsentrasi adalah perbandingan konsentrasi produk dipangkatkan kofisien terhadap konsentrasi pereaksi dipangkatkan koefisien. Pada suatu persamaan reaksi A open parentheses g close parentheses and 2 B open parentheses g close parentheses equilibrium AB subscript 2 open parentheses g close parentheses, Kc dapat dicari dengan cara:

table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript c end cell equals cell open square brackets produk close square brackets to the power of koef over open square brackets pereaksi close square brackets to the power of koef end cell row cell K subscript c end cell equals cell fraction numerator open square brackets AB subscript 2 close square brackets to the power of 1 over denominator open square brackets A close square brackets to the power of 1 left square bracket 2 B right square bracket squared end fraction end cell end table

 

Maka, persamaan konstanta keseitmbangan berdasarkan konsentrasinya adalah:


K subscript c equals fraction numerator open square brackets N subscript 2 close square brackets squared open square brackets H subscript 2 O close square brackets to the power of 6 over denominator open square brackets N H subscript 3 close square brackets to the power of 4 open square brackets O subscript 2 close square brackets cubed end fraction


Jadi, jawaban yang tepat adalah C.space

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