Roboguru

Gunakan rumus Balmer untuk menghitung panjang gelombang tiga garis pertama dari deret Lyman!

Pertanyaan

Gunakan rumus Balmer untuk menghitung panjang gelombang tiga garis pertama dari deret Lyman!

Pembahasan Soal:

begin mathsize 14px style 1 over lambda subscript 1 equals R open parentheses 1 over 1 squared minus 1 over 2 squared close parentheses 1 over lambda subscript 1 equals 1 comma 097 cross times 10 to the power of 7 open parentheses 1 over 1 minus 1 fourth close parentheses 1 over lambda subscript 1 equals 1 comma 097 cross times 10 to the power of 7 open parentheses fraction numerator 4 minus 1 over denominator 4 end fraction close parentheses 1 over lambda subscript 1 equals 1 comma 097 cross times 10 to the power of 7 open parentheses 3 over 4 close parentheses 1 over lambda subscript 1 equals 0 comma 82 cross times 10 to the power of 7 lambda subscript 1 equals fraction numerator 1 over denominator 0 comma 82 cross times 10 to the power of 7 end fraction equals 1 comma 22 cross times 10 to the power of negative 7 end exponent space straight m   1 over lambda subscript 2 equals R open parentheses 1 over 2 squared minus 1 over 3 squared close parentheses 1 over lambda subscript 2 equals 1 comma 097 cross times 10 to the power of 7 open parentheses 1 fourth minus 1 over 9 close parentheses 1 over lambda subscript 2 equals 1 comma 097 cross times 10 to the power of 7 open parentheses fraction numerator 9 minus 4 over denominator 36 end fraction close parentheses 1 over lambda subscript 2 equals 1 comma 097 cross times 10 to the power of 7 open parentheses 5 over 36 close parentheses 1 over lambda subscript 2 equals 0 comma 15 cross times 10 to the power of 7 lambda subscript 2 equals fraction numerator 1 over denominator 0 comma 15 cross times 10 to the power of 7 end fraction equals 6 comma 67 cross times 10 to the power of negative 7 end exponent space straight m   1 over lambda subscript 3 equals R open parentheses 1 over 3 squared minus 1 over 4 squared close parentheses 1 over lambda subscript 3 equals 1 comma 097 cross times 10 to the power of 7 open parentheses 1 over 9 minus 1 over 16 close parentheses 1 over lambda subscript 3 equals 1 comma 097 cross times 10 to the power of 7 open parentheses fraction numerator 16 minus 9 over denominator 144 end fraction close parentheses 1 over lambda subscript 3 equals 1 comma 097 cross times 10 to the power of 7 open parentheses 7 over 144 close parentheses 1 over lambda subscript 3 equals 0 comma 053 cross times 10 to the power of 7 lambda subscript 3 equals fraction numerator 1 over denominator 0 comma 053 cross times 10 to the power of 7 end fraction equals 18 comma 87 cross times 10 to the power of negative 7 end exponent space straight m end style   

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 13 Maret 2021

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