Fungsi kerja wolfram ialah 4,58 eV. a. Carilah frekuensi dan panjang gelombang ambang untuk efek fotolistrik. b. Carilah potensial hentinya jika panjang gelombang cahaya yang datang sama dengan 200 nm dan 250 nm.

Pertanyaan

Fungsi kerja wolfram ialah 4,58 eV.

a. Carilah frekuensi dan panjang gelombang ambang untuk efek fotolistrik.
b. Carilah potensial hentinya jika panjang gelombang cahaya yang datang sama dengan 200 nm dan 250 nm. $\;$

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Pembahasan Video:

Pembahasan Soal:

Diketahui:

$begin mathsize 14px style capital phi equals 4 , 58 blank eV h equals 4 , 14 cross times 10 to the power of negative 15 end exponent blank eVs c equals 3 cross times 10 to the power of 8 blank straight m divided by straight s lambda subscript italic 1 equals 200 blank nm lambda subscript italic 2 equals 250 blank nm end style$

Ditanyakan:

$begin mathsize 14px style straight a. space f subscript 0 equals ? semicolon blank lambda subscript 0 equals ? straight b. italic space V subscript italic 1 equals ? semicolon blank V subscript italic 2 equals ? end style$

Penyelesaian:

a. Frekuensi dan panjang gelombang ambang

$begin mathsize 14px style capital phi equals h f subscript 0 f subscript 0 equals capital phi over h f subscript 0 equals fraction numerator 4 , 58 blank eV over denominator 4 , 14 cross times 10 to the power of negative 15 end exponent blank eVs end fraction f subscript 0 equals 1 , 11 cross times 10 to the power of 15 blank Hz lambda subscript 0 equals c over f subscript 0 lambda subscript 0 equals fraction numerator 3 cross times 10 to the power of 8 over denominator 1 , 11 cross times 10 to the power of 15 end fraction lambda subscript 0 equals 2 , 703 cross times 10 to the power of negative 7 end exponent straight m straight lambda subscript 0 equals 270 , 3 blank nm end style$

b. Potensial henti

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell E subscript k comma e l e t r o n end subscript end cell equals cell E subscript f o t o n end subscript minus capital phi end cell row cell e V end cell equals cell h c over lambda minus capital phi end cell row blank blank blank row cell e V subscript 1 end cell equals cell 4 , 14 cross times 10 to the power of negative 15 end exponent fraction numerator 3 cross times 10 to the power of 8 over denominator 200 cross times 10 to the power of negative 9 end exponent end fraction minus 4 , 58 end cell row blank blank blank row cell e V subscript 1 end cell equals cell 6 , 21 minus 4 , 58 end cell row cell e V subscript 1 end cell equals cell 1 , 63 blank e straight V end cell row cell V subscript italic 1 end cell equals cell 1 , 63 blank straight V end cell row blank blank blank row cell e V subscript italic 2 end cell equals cell 4 , 14 cross times 10 to the power of negative 15 end exponent fraction numerator 3 cross times 10 to the power of 8 over denominator 250 cross times 10 to the power of negative 9 end exponent end fraction minus 4 , 58 end cell row cell e V subscript italic 2 end cell equals cell 4 , 97 minus 4 , 58 end cell row cell e V subscript italic 2 end cell equals cell 0 , 39 blank e straight V end cell row cell V subscript italic 2 end cell equals cell 0 , 39 blank straight V end cell end table end style$

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

S. Syifa

Terakhir diupdate 05 Oktober 2021