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Pertanyaan

Es dengan massa 200 gram bersuhu - 5 0C dicampur dengan sejumlah air bersuhu 30 0C sehungga mencapai keadaan akhir berupa seluruhnya bersuhu 0 0C. Kalor jenis es begin mathsize 14px style 0 comma 5 space kal. straight g to the power of negative 1 end exponent. space to the power of straight o straight C to the power of negative 1 end exponent end style. Kalor lebur es begin mathsize 14px style 80 space kal. straight g to the power of negative 1 end exponent end style, dan kalor jenis air begin mathsize 14px style 1 space kal. straight g to the power of negative 1 end exponent. space to the power of straight o straight C to the power of negative 1 end exponent end style. Massa air mula-mula adalah ....

  1. 0,10 kg

  2. 0,15 kg

  3. 0,25 kg

  4. 0,35 kg

  5. 0,55 kg

R. Maiza

Master Teacher

Mahasiswa/Alumni Institut Teknologi Bandung

Jawaban terverifikasi

Pembahasan

straight m subscript es equals 0 comma 2 space kg equals 200 space straight g  straight T subscript es equals negative 5 space degree straight C  straight T subscript air equals 30 space degree straight C  straight T subscript straight c equals 0 space degree straight C semicolon space melebur space seluruhnya  straight c subscript es equals 0 comma 5 space kal divided by straight g. degree straight C  straight L subscript es equals 80 space kal divided by straight g  straight c subscript air equals 1 space kal divided by straight g. degree straight C  straight m subscript air ?    Asas space Black  straight Q subscript lepas equals straight Q subscript terima  straight m subscript air. straight c subscript air. increment straight T equals straight m subscript es. straight c subscript es. increment straight T plus straight m subscript es. straight L subscript es  straight m subscript air. straight c subscript air. left parenthesis straight T subscript air minus straight T subscript straight c right parenthesis equals straight m subscript es. straight c subscript es. left parenthesis straight T subscript straight c minus straight T subscript es right parenthesis plus straight m subscript es. straight L subscript es  straight m subscript air. left parenthesis 1 right parenthesis left parenthesis 30 minus 0 right parenthesis equals left parenthesis 200 right parenthesis left parenthesis 0 comma 5 right parenthesis left parenthesis 0 minus left parenthesis negative 5 right parenthesis right parenthesis plus left parenthesis 200 right parenthesis left parenthesis 80 right parenthesis  30 space straight m subscript air space equals space 500 plus 16000  straight m subscript air equals 16500 over 30 equals 550 space gram  straight m subscript air equals 0 comma 55 space kg

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Ke dalam bejana yang mempunyai kapasitas kalor 5 kal/ºC dimasukkan 300 g air yang bersuhu 20ºC, kemudian dimasukkan 100 g es yang bersuhu -4ºC. Setelah diaduk, berapa gram es yang belum melebur?

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