Roboguru

Diketahui , tentukan

Pertanyaan

Diketahui begin mathsize 14px style h open parentheses x close parentheses equals x squared minus 2 x plus 4 end style, tentukan begin mathsize 14px style h to the power of negative 1 end exponent open parentheses x close parentheses equals horizontal ellipsis end style   

  1. begin mathsize 14px style plus-or-minus square root of x minus 3 end root minus 1 end style 

  2. size 14px plus-or-minus square root of size 14px x size 14px plus size 14px 3 end root size 14px plus size 14px 1 

  3. size 14px plus-or-minus square root of size 14px x size 14px minus size 14px 3 end root size 14px plus size 14px 1 

  4. size 14px plus-or-minus square root of size 14px minus size 14px x size 14px minus size 14px 3 end root size 14px plus size 14px 1 

  5. size 14px plus-or-minus square root of size 14px minus size 14px x size 14px minus size 14px 3 end root size 14px minus size 14px 1 

Pembahasan Soal:

Diketahui begin mathsize 14px style h open parentheses x close parentheses equals x squared minus 2 x plus 4 end style, maka begin mathsize 14px style h to the power of negative 1 end exponent open parentheses x close parentheses end style adalah

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell h left parenthesis x right parenthesis end cell equals cell x squared minus 2 x plus 4 end cell row cell h left parenthesis x right parenthesis end cell equals cell left parenthesis x minus 1 right parenthesis squared plus 3 end cell row cell space y end cell equals cell left parenthesis x minus 1 right parenthesis squared plus 3 end cell row cell y minus 3 end cell equals cell left parenthesis x minus 1 right parenthesis squared space end cell row cell left parenthesis x minus 1 right parenthesis squared end cell equals cell y minus 3 end cell row cell x minus 1 end cell equals cell plus-or-minus square root of y minus 3 end root end cell row x equals cell plus-or-minus square root of y minus 3 end root plus 1 end cell row cell h to the power of negative 1 end exponent left parenthesis y right parenthesis end cell equals cell plus-or-minus square root of y minus 3 end root plus 1 end cell row cell h to the power of negative 1 end exponent left parenthesis x right parenthesis end cell equals cell plus-or-minus square root of x minus 3 end root plus 1 end cell end table end style 

Jadi, jawaban yang tepat adalah C. 

 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 15 Maret 2021

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